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Y_Kistochka [10]
3 years ago
15

Is a line is represented by a straight narrow segment with arrow signs at the end? ...?

Mathematics
1 answer:
Luda [366]3 years ago
8 0
Yes, as a line is a continuous object; it's infinite. A line segment is what you would use in a number line, per se.
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Rational exponents: product rule<br> simplify<br> v^3/4 multiply v^5/7
marusya05 [52]

Answer:

  v\sqrt[28]{v^{13}}

Step-by-step explanation:

The exponent rules that apply are ...

(a^b)(a^c)=a^{b+c}\\\\a^{\frac{b}{c}}=\sqrt[c]{a^b}

Using these rules for your product, we have ...

v^{\frac{3}{4}}\times v^{\frac{5}{7}}=v^{\frac{3}{4}+\frac{5}{7}}\\\\=v^{\frac{41}{28}}=v\cdot v^{\frac{13}{28}}=v\sqrt[28]{v^{13}}

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3 years ago
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Answer:

Step-by-step explanation:

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4 0
4 years ago
Read 2 more answers
A. What are the coordinates of the vertices of the triangle below?
Viktor [21]

Answer:

Solution given:

<u>A.coordinate are</u>

A(-2,3)

B(0,-3)

C(4,5)

<u>B</u><u>.</u><u>Each</u><u> </u><u>length</u><u> </u><u>are</u><u> </u><u>:</u>

we have

length \sqrt{(x2-x1)²+(y2-y1)²}

now

AB:\sqrt{(-2-0)²+(3+3)²}=2\sqrt{10}units

BC:\sqrt{(0-4)²+(-3-5)²}=4\sqrt{5}units

AC:\sqrt{(-2-4)²+(3-5)²}=2\sqrt{10}units

<u>C.</u><u> the </u><u>figure</u><u>:</u>

<u>By</u><u> </u><u>using</u><u> </u><u>Pythagoras</u><u> </u><u>law</u>

base[b]=AB=perpendicular [p]=AC

hypotenuse [h]=BC

we have

h²=p²+b²

substituting value

(4\sqrt{5})²=2p²

16*5=2*(2\sqrt{10})²

80=2*4*10

80=80

<u>SO</u><u> </u><u>IT</u><u> </u><u>IS</u><u> </u><u>RIGHT</u><u> </u><u>ANGLED</u><u> </u><u>ISOSCELES</u><u> </u><u>TRIANGLE</u><u>.</u>

4 0
3 years ago
If you got your 60% discount and opened up the card for an additional 20%, what is the actual % discount you would receive?
Alinara [238K]

Answer:

80 I guess.................

6 0
3 years ago
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BARSIC [14]

Answer:

Use https://www.bartleby.com/  it has helped me out a lot . Its actual tutors/teachers who answer your questions in about 30 minutes :)

Step-by-step explanation:

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