if the ellipse has a major axis of 12 inches, that means its major radius is half that, or 6, and if its minor axis is 7, then its minor radius is half that, 3.5.
![\bf \textit{volume of an elliptical cylinder}\\\\ V=\pi ab h~~ \begin{cases} a=\textit{major axis radius}\\ b=\textit{minor axis radius}\\ h=height\\[-0.5em] \hrulefill\\ a=6\\ b=3.5\\ h=21 \end{cases} \\\\\\ V=\pi (6)(3.5)(21)\implies V\approx 1385.44236023309881816203](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20an%20elliptical%20cylinder%7D%5C%5C%5C%5C%0AV%3D%5Cpi%20ab%20h~~%0A%5Cbegin%7Bcases%7D%0Aa%3D%5Ctextit%7Bmajor%20axis%20radius%7D%5C%5C%0Ab%3D%5Ctextit%7Bminor%20axis%20radius%7D%5C%5C%0Ah%3Dheight%5C%5C%5B-0.5em%5D%0A%5Chrulefill%5C%5C%0Aa%3D6%5C%5C%0Ab%3D3.5%5C%5C%0Ah%3D21%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0AV%3D%5Cpi%20%286%29%283.5%29%2821%29%5Cimplies%20V%5Capprox%201385.44236023309881816203)
Answer:
Step-by-step explanation:
ggh
Answer:
Answer should be C
Step-by-step explanation:
Im not entirely sure
Answer:
I. 60%
II. 75.4 kg
Step-by-step explanation:
We will use the z-scores and the standard normal distribution to answer this questions.
We have a normal distribution with mean 69 kg and variance 25 kg^2 (therefore, standard deviation of 5 kg).
I. What percentage of adult male in Boston weigh more than 72 kg?
We calculate the z-score for 72 kg and then calculate the associated probability:

II. What must an adult male weigh in order to be among the heaviest 10% of the population?
We have to calculate tha z-score that satisfies:

This happens for z=1.28 (see attachment).
Then, we can calculate the weight using this transformation:

Answer:
14a² - 3b² + 4b
Step-by-step explanation:
Like terms are the terms that have similar stuff on it, like same variables, no variables, and stuff like that.
4a2-3b2+ 4b + 10a2
4a² and 10a² is similar. 4a² + 10a² = 14a²
Now, the equation is 14a² - 3b² + 4b. There is no more like terms left, so that is the answer.
Hope this helps!!
-Ketifa