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3 years ago

If the degree in the numerator is smaller than the degree in the denominator and there is no vertical

Mathematics

2 answers:

mote1985 [20]3 years ago

8 0

The answer is false.

AfilCa [17]3 years ago

6 0

Step-by-step explanation:

what do u think ?

not always true so the answer is false

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Vladimir buys 1.20 pounds of Skittles, 312 pounds of M&Ms, and 5.2 pounds of pretzels. If the candy cost $1.20 a pound and t

BlackZzzverrR [31]

Answer: $10.90

Step-by-step explanation:

Skittles-1.44

M&M's-3.744

Pretzels-5.72

Not sure if its a typo, thats if theres 3.12lbs of of M&M's

The answer is theres 312 M&M's is 374.4

6 0

3 years ago

HELP NEED HELP FAST ANSWER FAST PLEZ

vodomira [7]

Answer

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4 0

3 years ago

The total number of fans who went to watch professional soccer games in the last decade can be modeled by the function f(x)=x3+9

Pani-rosa [81]

Answer:

Step-by-step explanation:

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5 0

4 years ago

How far is 75% of a 2,000-kilometer trip

zubka84 [21]

Answer: 1500 kilometers

75% of a 2000 - kilometer trip is 1500 kilometers

Step-by-step explanation:

6 0

3 years ago

The circumference of the ellipse approximate. Which equation is the result of solving the formula of the circumference for b?

Serhud [2]

Answer:

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

Step-by-step explanation:

Given - The circumference of the ellipse approximated by $C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }$ where 2a and 2b are the lengths of 2 the axes of the ellipse.

To find - Which equation is the result of solving the formula of the circumference for b ?

Solution -

$C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }\\\frac{C}{2\pi } = \sqrt{\frac{a^{2} + b^{2} }{2} }$

Squaring Both sides, we get

$[\frac{C}{2\pi }]^{2} = [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2} } = {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2} } = {{a^{2} + b^{2} }$

$\frac{C^{2} }{2(\pi )^{2} } = a^{2} + b^{2} \\\frac{C^{2} }{2(\pi )^{2} } - a^{2} = b^{2} \\\sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}} = b$

∴ we get

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

8 0

3 years ago