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earnstyle [38]
3 years ago
13

A children's pool contains 17,500 milliliters. How many liters are in the pool

Mathematics
1 answer:
OlgaM077 [116]3 years ago
8 0

Answer:

17.5

Step-by-step explanation:

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Is 5.3 repeating rational
Goshia [24]

Repeating decimals are considered rational numbers because they can be represented as a ratio of two integers. If a number is terminating or repeating, it must be rational if a decimal is both non terminating and non repeating, the number is irrational.

So yes.

4 0
3 years ago
Which of the following numbers are divisible by 2 3 and 6 grad 7 ​
Ray Of Light [21]

Answer:

Is there any picture for it?

Step-by-step explanation:

6 0
3 years ago
Two lengths are in the ratio 2:5. The second length is 75 cm. Find the first length.​
vichka [17]

Answer:

30 cm

Step-by-step explanation:

2 * 15: 5 * 15

    30:75

7 0
3 years ago
Find the vertex.<br> f(x)<br> =<br> 2(x + 7)2 + 8<br> ([?],[ ]
Nana76 [90]
(-7,8)

Simplifying 2(x+7)^2+8
Will give you the image results

You must graph the formula and you’ll get -7,8 (using desmos helps)

6 0
3 years ago
How to find function definition area
insens350 [35]

Answer:Definition area"? Do you mean the "natural domain" of the function- the region in which the formula is defined? In order that a number have a square root that number must be non-zero.

Step-by-step explanation:Here, we must have x−1x≥0.

If x is positive, multiplying both sides by x we have x2−1=(x−1)(x+1)≥0. In order for that to be true, both x- 1 and x+ 1 must have the same sign: either x-1> 0 and x+ 1> 0 or x- 1< 0 and x+ 1< 0. The first pair of inequalities is true for x> 1 and the second for x< -1. Since "x is positive", we must have x> 1.

If x is negative, multiplying both sides by x we have x2−1=(x−1)(x+1)≥0. In order for that to be true, x- 1 and x+ 1 must have opposite signs: x+ 1> 0 and x- 1< 0 or x- 1<0 and x- 1> 0. The first pair is true for −1≤0≤1. The second pair are never both true. Since "x is negative" we must have −1≤x≤0.

Of course, we also cannot divide by 0 so x= 0 is not in the domain. The domain is the union of the two separate sets:{x|−1≤x<0}∪{x|x>1}.

Hope That Helps!

8 0
3 years ago
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