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pshichka [43]
3 years ago
10

Evaluate the expression for X=2 and y=4. enter your answer in the box.

Mathematics
1 answer:
kondaur [170]3 years ago
8 0

Answer:

18

Step-by-step explanation:

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A fruit company delivers its fruit in two types of boxes: large and small. A delivery of 5 large boxes and 6 small boxes has a t
Mekhanik [1.2K]

Answer:

Large Box = 18.5

Small Box = 15.75

Step-by-step explanation:

Let x = large box and y = small box

5x+6y=187

3x+2y=87

cancel out one equation

(5x+6y=187)•3=15x+18y=561

(3x+2y=87)•-5=15x+10y=435

 15x+18y=561

-15x-10y=-435

–––––––––––

 0+ 8y= 126

  8y÷8 =126÷8

y=15.75

Substitute y into either original equation

3x+2(15.75)=87

3x+ 31.5=87

3x+ 31.5-31.5=87-31.5

3x=55.5

3x÷3=55.5÷3

x=18.5

5 0
4 years ago
Let the graph of g be a translation 3 units up, followed by a vertical stretch by a factor of 2 and a reflection in the x-
Keith_Richards [23]

Answer:

The answer is g(x)= -6x(x-1)+3

Step-by-step explanation:

we know that f(x) is written as 3x^{2}-3x

to show that the graph is being translated up, vertically stretching, and reflecting across the x axis, we need to factor the function.

f(x)= 3x^{2}-3x \\    3x(x-1)\\

now we can incorporate the changes to this graph.

multiply 3x by 2 and -1. (2 for a stretch and -1 for a reflection).

-6x(x-1)

tack on the +3 to show a translation of 3 units up.

-6x(x-1)+3

therefore, g(x)= -6x(x-1)+3

hope this helps!

5 0
3 years ago
Please help ! only G-J 15 points for this.
kogti [31]

Answers: G) ∠BCS = 57.5°

                H) ∠FHI = 72°

                 I) ∠ACB and also ∠DCH

                 J) ∠CHD (which can also be named ∠BHE)

<u>Step-by-step explanation:</u>

First of all, I checked your answers for A-F and they are all correct. YAY!

********************************************************************************************

G) Draw a point halfway between B and D and label it S. Then draw a ray from C passing through S.

∠ACB and ∠BCD are supplementary so

  65°    +    ∠BCD  =     180°

⇒               ∠BCD  =     115°

Since ray CS bisects ∠BCD, then ∠BCS is half of ∠BCD.

\angle BCS=\dfrac{1}{2} (\angle BCD)\\\\. \quad \quad=\dfrac{1}{2}(115^o)\\\\. \quad \quad =\large\boxed{57.5^o}

********************************************************************************************

H) The instructions state to draw a line from H to F.  This divides ∠DHI into two angles: ∠FHD and ∠FHI.  Since lines BI and EG are perpendicular, then ∠DHI = 90°.  It is given that ∠FHI is 4 times larger than ∠FHD so we can use substitution...

∠FHD + ∠FHI = ∠DHI

∠FHD + 4(∠FHD) = 90°

             5(∠FHD) = 90°

                ∠FHD  = 18°

∠FHI = 4(∠FHD)

        = 4 (18°)

        = \large\boxed{72^o}

********************************************************************************************

I) adjacent means they share a side and supplementary means they form a straight angle. There are two angles that are adjacent and supplementary to ∠ACH.  

  • ACB - they share side AC and are supplementary on BH
  • DCH - they share side CH and are supplementary on AD

********************************************************************************************

J) congruent means equal and adjacent means they share a side.

The angle that is not congruent nor adjacent to ∠GHI is its vertical angle, which is ∠CHD.  <em>Notice that ∠CHD is the same as ∠BHE.</em>

5 0
3 years ago
Point A(7.3) is translated to A’(16,-9) Which rule describes the translation?
alexandr402 [8]
I believe the answer is

(x,y)-> (x+9,y-12)
3 0
4 years ago
Which property justifies the following equation?
lana [24]
I believe it is C because the Associative property states that no matter how you use your parenthesis the answer will be the same <span />
8 0
3 years ago
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