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2 years ago

What is the slope of the line y= 3?

Mathematics

2 answers:

Taya2010 [7]2 years ago

5 0

In y = mx + b, m = slope. Since there is no m or x, m much be 0.
The slope of the line is 0 (horizontal line).

Kipish [7]2 years ago

4 0

Answer:

Undefined

Step-by-step explanation:

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frutty [35]

Answer:

$y=\dfrac{3x}{e}+\dfrac{4}{e}$

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Step-by-step explanation:

to find the tangent line we need to find the derivative of the function g(x).

$g(x) =e^{x^3}$

we know that $\frac{d}{dx}(e^{f(x)})=e^{f(x)}f'(x)$

$g'(x) =e^{x^{3}}(3 x^{2})$

$g'(x) =3 x^{2} e^{x^{3}}$

this the equation of the slope of the curve at any point x and it also the slope of the tangent at any point x. hence, g'(x) can be denoted as 'm'

to find the slope at (-1,1/e) we'll use the x-coordinate of the point i.e. x = -1

$m =3 (-1)^{2} e^{(-1)^{3}}\\m =3e^{-1}\\m=\dfrac{3}{e}$

using the equation of line:

$(y-y_1)=m(x-x_1)$

we'll find the equation of the tangent line.

here (x1,y1) =(-1,1/e), and m = 3/e

$(y-\dfrac{1}{e})=\dfrac{3}{e}(x+1)\\y=\dfrac{3x}{e}+\dfrac{3}{e}+\dfrac{1}{e}\\$

$y=\dfrac{3x}{e}+\dfrac{4}{e}$

this is the equation of the tangent at point (-1,1/e)

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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SVEN [57.7K]

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Read 2 more answers

Nick and Monica are paid $41.25 for their work. Nick worked 2.5 hours, and Monica worked 3 hours. They split the money according

vlada-n [284]

Answer:

BRIANLIEST PLZ

N = 18.75

M = 22.5

Step-by-step explanation:

Need the ratio of money paid to each. We know how the ratio of time is divided so we can use this ratio to find the amount paid.

T = t1 + t2 = 2.5 + 3 = 5.5

r1 =2.5/5.5

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