Answer:
We can claim with 95% confidence that the proportion of executives that prefer trucks is between 19.2% and 32.8%.
Step-by-step explanation:
We have a sample of executives, of size n=160, and the proportion that prefer trucks is 26%.
We have to calculate a 95% confidence interval for the proportion.
The sample proportion is p=0.26.
The standard error of the proportion is:
The critical z-value for a 95% confidence interval is z=1.96.
The margin of error (MOE) can be calculated as:

Then, the lower and upper bounds of the confidence interval are:

The 95% confidence interval for the population proportion is (0.192, 0.328).
We can claim with 95% confidence that the proportion of executives that prefer trucks is between 19.2% and 32.8%.
Step-by-step explanation:
-4(4x-9)=2x
-16x+36= 2x
-16x - 2x = -36
-18x = -36
x = 2
Answer:
n= 4f/5+90
Step-by-step explanation:
f= 5(n−90)
/4 (simplify)
f * 4=5(n−90) (multiply 4 on both sides)
4f=5(n−90) (regroup)
4f/5
=n−90 (divide 5 on both sides)
4f/5
+90=n (add 90 to both sides)
Answer:
C
Step-by-step explanation:
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