All categories

3 years ago

-7 opposite and absolute value

Mathematics

2 answers:

77julia77 [94]3 years ago

7 0

It is 7 opposite is different and absolute value would be 7 also it is always positive

vesna_86 [32]3 years ago

5 0

The absolute value is +7. for future references, just remember if it has so negative, the absolute value will be -7... vice versa haha:)

You might be interested in

I WILL MARK BRAINLIEST

vagabundo [1.1K]

Answer:

$\frac{81}{m^7}$

Step-by-step explanation:

We have a certain expression and are asked to find its equivalent with the answers provided :

$(3m^{-4} )^3(3m^5)$

Remove the parenthesis around 3m^5 :

$(3m^{-4} )^3*3m^5$

Do the exponent rule for outside and inside exponent parenthesis :

$(3m^{-4*3} )$

$3^3m^{-12} *3m^5$

Apply addition exponent rule :

$m^{-12} *3^{3+1} m^5$

Add :

$m^{-12} *3^4m^5$

Apply the addition rule for -12 + 5 :

$3^{4} m^{-7}$

Apply negative exponent rule for m^-7 :

$3^4*\frac{1}{m^7}$

Multiply the fractions :

$\frac{1*3^4}{m^7}$

$\frac{81}{m^7}$

3 0

2 years ago

The last question I need help on.

AleksAgata [21]

An ecosystem is a geographic area where plants, animals, and other organisms, as well as weather and landscape, work together to form a bubble of life.

8 0

2 years ago

Calculate limits x>-infinity<br> -2x^5-3x+1

Lera25 [3.4K]

Given:

The limit problem is:

$\lim_{x\to -\infty}(-2x^5-3x+1)$

To find:

The value of the given limit problem.

Solution:

We have,

$\lim_{x\to -\infty}(-2x^5-3x+1)$

In the function $-2x^5-3x+1$ , the degree of the polynomial is 5, which is an odd number and the leading coefficient is -2, which is a negative number.

So, the function approaches to positive infinity as x approaches to negative infinity.

$\lim_{x\to -\infty}(-2x^5-3x+1)=\infty$

Therefore, $\lim_{x\to -\infty}(-2x^5-3x+1)=\infty$ .

3 0

2 years ago

A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30 What score is necessary to reach

nlexa [21]

Answer:

A score of 150.25 is necessary to reach the 75th percentile.

Step-by-step explanation:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30.

This means that $\mu = 130, \sigma = 30$