Answer: 22
explanation: the easiest way is to separate one of the diagonals into a triangle and use the pythagorean theorem.
a^2 + b^2 = c^2
4^2 + 3^3 = c^2
16 + 9 = c^2
25 = c^2
5 = c
you now know that both of the diagonals have a length of 5.
by counting the units on the two straight, you know that their length is 6.
6 + 6 + 5 + 5 = 22
9^1/3 * 3^x = 27^4/5
Rewrite 9 as 3^2
(3^2)^1/3 * 3^x = 27^4/5
Multiply the exponents in the first term:
3^2/3 * 3^x = 27^4/5
Use power rule to combine exponents:
3^(2/3 +x) = 27^4/5
Rewrite the 2nd term:
3^(2/3 +x) = (3^3)^4/5
Set the exponents only to equal:
2/3 + x = 3(4/5)
Solve for x:
simplify the right side:
2/3 + x = 12/5
Subtract 2/3 from both sides:
x = 26/15
It would be 0.125 for the first answer
Answer:
7168
Step-by-step explanation:
