Write 2 4 over 9 as an improper fraction

Belinda builds a rectangular prism that is 2 cubes long, 3 cubes wide, and 2 cubes tall. Each dimension of April's rectangula

zepelin [54]

Answer:

96 cubes vol.

Step-by-step explanation:

the volume of Belinda's prism =

2×3×2 = 12 cubes vol.

Each dimension of April's rectangular prism is twice as many cubes as Belinda's prism.

the volume of April's prism =

(2×2)×(2×3)×(2×2)= 4×6×4= 96 cubes vol.

so,

the volume of April's prism = (2)³ times the volume of Belinda's prism

4 0

3 years ago

Anyone know how to check solution, please help if u do

Ivenika [448]

Let's check your answer. To do this, you would simply plug your answer into the equation and see if it works.
5(y - 3) - 2 (3 - 2y) = 6
5(3 - 3) - 2(3 - 2 × 3) = 6

The equation works!

Y = 3

Great work!

3 0

3 years ago

An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s

Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is 0.5 s and 7 s.

Step-by-step explanation:

Given:

Initial speed of debris is, $s=120\ ft/s$

The height 'h' of the debris above the ground is given as:

$h(t)=-16t^2+120t$

As per question, $h(t)=56\ ft$ . Therefore,

$56=-16t^2+120t$

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

$-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0$

Using quadratic formula to solve for 't', we get:

$t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s$