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yawa3891 [41]
3 years ago
13

Find the smallest positive integer that must be added to 2010 to obtain a perfect square

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
5 0

Answer:

15

Step-by-step explanation:

Take the square root of 2010: \sqrt{2010} =44.833...

Round this value up: 45

Square the number: 45^{2} =2025

2025 is the closest number to 2010 that is a perfect square.

Difference: 2025-2010=15

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Write the numbers in order from least to greatest.<br> 1.23, 2.13, 3.12, 1.11
nadya68 [22]

Answer:

1.11,1.23,2.13, 3.12

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The digits of a two-digit number sum to 8. When the digits are reversed the resulting number is 18 less than the onginal
polet [3.4K]

Answer:

53

Step-by-step explanation:

Given: The sum of two digit number is 8

           Reversing the digit will get us number 18 less than the original.

Lets take x as tenth digit of our number and y as unit digit of our number.

As given sum of digit is 8

∴ x+y= 8

∴ y= 8-x -       equation 1

We also know that reversing the digit will get us number 18 less than the original.

∴ 10y+x = 10x +y-18

Now, lets put the value of y from equation 1

⇒ 10(8-x) + x = 10x+ (8-x)- 18

⇒ 80-9x= 9x-10

⇒ 90= 18x

∴ x= 5

Next, substituting the value of x in equation 1

y= 8-x

⇒ y= 8-5 = 3

∴ y= 3

∴ The original number is 53, sum of the digit is 8 and if we reverse the digit of the number, we get 35, which is 18 less than the original number.

7 0
3 years ago
Expansion Numerically Impractical. Show that the computation of an nth-order determinant by expansion involves multiplications,
posledela

Answer:

  • number of multiplies is n!
  • n=10, 3.6 ms
  • n=15, 21.8 min
  • n=20, 77.09 yr
  • n=25, 4.9×10^8 yr

Step-by-step explanation:

Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...

  mpy[n] = n·mp[n-1]

  mpy[2] = 2

So, ...

  mpy[n] = n! . . . n ≥ 2

__

If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...

  10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10

Then the larger matrices take ...

  n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min

  n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years

  n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years

_____

For the shorter time periods (less than 100 years), we use 365.25 days per year.

For the longer time periods (more than 400 years), we use 365.2425 days per year.

8 0
3 years ago
What is the prime factorization of 75,29, and 168
Anna35 [415]

Answer:

Step-by-step explanation:

75 = 5 *5* 3

29 is a prime number = 29*1

168 = 2*2*2*3*7

7 0
3 years ago
What is the value of the expression 30 - 9+ 3 - (12 = 4)?
Flauer [41]

Answer:

21

Step-by-step explanation:

30 - 9 +3

30 - 12

18

18 - 12=4

      12/4 = -3

18 - -3

21

8 0
2 years ago
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