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julia-pushkina [17]
4 years ago
13

Solving system of equations with substitution.

Mathematics
1 answer:
JulijaS [17]4 years ago
6 0

Answer:

Hope it helps!

Step-by-step explanation:

Sub y=5x into y=2x+3

so

5x=2x+3

3x=3

x=1

plug x=1 into y=5x

y=5

Checking work

Plug (1,5) into y=2x+3

5=2(1)+3

5=5

Plug (1,5) into y=5x

5=5(1)

5=5

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These are easy if you know  " FOIL ".  That's a procedure that takes you through multiplying two binomials.

FOIL stands for
-- <u><em>F</em></u>irst terms
<span>-- </span><u><em>O</em></u>utside terms
<span>--<em> </em></span><u><em>I</em></u>nside terms
<span>--<em> </em><u><em>L</em></u></span>ast terms

and that's how you keep everything straight while you're doing it.

(ax + b) x (cx + d)

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Multiply Last terms . . .  'b' times 'd' =  <em>bd</em>

Now addummup:

(ax + b) x (cx + d)  =  <em>acx² + adx + bcx + bd</em>

From there, you can look for opportunities to make it look cleaner and prettier ... factoring, combining like terms, etc.

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4 years ago
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