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3 years ago

What is the factored form of 64g^3+8

Mathematics

1 answer:

IrinaK [193]3 years ago

4 0

Answer:

8(2g + 1)(4g² - 2g + 1)

Step-by-step explanation:

Given

64g³ + 8 ← factor out 8 from each term

= 8(8g³ + 1) ← 8g³ + 1 is a sum of cubes and factors as

8g³ + 1 = (2g + 1)((2g)² - 2g + 1² ) = (2g + 1)(4g² - 2g + 1)

Hence

64g³ + 8 = 8(2g + 1)(4g² - 2g + 1)

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EastWind [94]

The answer is 14 my name is freind45

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3 years ago

In a freshman class of 80 students,22 students take Consumer Education,20 students take French,and 4 students take both.Which eq

MAXImum [283]

<h3>Answer: Choice C</h3>

P = 11/40 + 1/4 - 1/20

=========================================================

Explanation:

The formula we use is

P(A or B) = P(A) + P(B) - P(A and B)

In this case,

P(A) = 22/80 = 11/40 = probability of picking someone from consumer education
P(B) = 20/80 = 1/4 = probability of picking someone taking French
P(A and B) = 4/80 = 1/20 = probability of picking someone taking both classes

So,

P(A or B) = P(A) + P(B) - P(A and B)

P(A or B) = 11/40 + 1/4 - 1/20

which is why choice C is the answer

----------------

Note: P(A and B) = 1/20 which is nonzero, so events A and B are not mutually exclusive.

6 0

3 years ago

Simplify the sum<br> (4u^3 + 4u^2 + 2) + (6u^3 - 2u + 8)

Lilit [14]

Answer:

$10u^3 + 4u^2 - 2u + 10$

Step-by-step explanation:

$(4u^3 + 4u^2 + 2) + (6u^3 - 2u + 8) \\ = 4u^3 + 4u^2 + 2 + 6u^3 - 2u + 8 \\ = 4u^3 +6u^3 + 4u^2 - 2u + 2 + 8 \\ = 10u^3 + 4u^2 - 2u + 10$

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3 years ago

Read 2 more answers

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earnstyle [38]

Answer:

Hello! if you have any more questions that I know I will answer!

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3 years ago

. The teacher decides that no student can win twice, so she removes the tickets of the first winner before drawing the second wi

Salsk061 [2.6K]

Answer:

<h2>There is 8% probability of Kitzen winning first and Ava second.</h2>

Step-by-step explanation:

The given table shows that there are 4 students, so there are 4 possible winner in total, but they have different number of tickets.

The total number of tickets is 48, that's the total possible outcomes. Kitzen has a probability of

$P_{Kitzen}=\frac{12}{48}=\frac{1}{4}$

Ava has a probability of

$P_{Ava}=\frac{16}{48}=\frac{1}{3}$

Now, the probability of having one event and the other is

$P=\frac{1}{4} \times \frac{1}{3}=\frac{1}{12} \approx 0.08$

Therefore, there is 8% probability of Kitzen winning first and Ava second.

(Notice that the probaility is not about Kitzen or Ava winning, it's about winning both, that's why the percentage is low)

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3 years ago