2 years ago

What is the factored form of 64g^3+8

Mathematics

1 answer:

IrinaK [193]2 years ago

4 0

Answer:

8(2g + 1)(4g² - 2g + 1)

Step-by-step explanation:

Given

64g³ + 8 ← factor out 8 from each term

= 8(8g³ + 1) ← 8g³ + 1 is a sum of cubes and factors as

8g³ + 1 = (2g + 1)((2g)² - 2g + 1² ) = (2g + 1)(4g² - 2g + 1)

Hence

64g³ + 8 = 8(2g + 1)(4g² - 2g + 1)

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