What is the factored form of 64g^3+8
1 answer:
Answer:
8(2g + 1)(4g² - 2g + 1)
Step-by-step explanation:
Given
64g³ + 8 ← factor out 8 from each term
= 8(8g³ + 1) ← 8g³ + 1 is a sum of cubes and factors as
8g³ + 1 = (2g + 1)((2g)² - 2g + 1² ) = (2g + 1)(4g² - 2g + 1)
Hence
64g³ + 8 = 8(2g + 1)(4g² - 2g + 1)
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