A ↔ B ↔ C ↔ D ↔ E ↔ F
8 7
???
AB + BC + CD = AD <em>segment addition postulate</em>
+ 8 + 7 = AD
+ 15 = AD
AD + 60 = 4AD
60 = 3AD
20 = AD
AB =
=
= 5
DE =
=
= 4
CD + DE + EF = CF <em>segment addition postulate</em>
7 + 4 + EF = CF
11 + EF = CF
Answer: 11 + EF
Note: You did not provide any info about EF. If you have additional information that you did not type in, calculate EF and add it to 11 to find the length of CF.
Bob has 7.5 pounds of flour
he wants to distribute the flour equally into 3 jars
how muc pounds in each jar
7.5/3=2.5 or 2 and 1/2 lb
A is the correct answer, NOT c. You don't list elements of the domain each time they occur, you enter each element of the domain only once
800×0.14=112
112+15=127
(127÷800)*100==15.88%