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Ymorist [56]
2 years ago
13

10, 30, 90 continue the pattern

Mathematics
2 answers:
Novosadov [1.4K]2 years ago
7 0
The answer is 270, the pattern is multiplying by 3. So, 10 • 3 = 30 30 • 3 = 90 90 • 3 = 270, and so on. Hope this helps! Let me know if you need any further assistant.
Step2247 [10]2 years ago
3 0

Answer:

  • geometric sequence: 10, 30, 90, 270, 810, 2430, ...
  • quadratic sequence: 10, 30, 90, 190, 330, 510, ...

Step-by-step explanation:

Three terms of a sequence can be the first three terms of many different kinds of sequences. Here the ratios of terms are constant:

  30/10 = 90/30 = 3

so the pattern could be that of a geometric sequence. In that sequence, each term is 3 times the previous one.

This pattern continues ...

  10, 30, 90, 270, 810, 2430, ...

___

Another way to look at sequences of numbers is to consider their differences. Here the differences are not constant, and there aren't enough terms to tell how the differences change.

  30 -10 = 20

  90 -30 = 60

The second of these differences can be viewed several ways. One is to say that it is 40 more than the first of the differences. If each successive difference is 40 more than the last, then the pattern is described by a quadratic function:

  a_n=10+20(n-1)^2

This pattern continues ...

  10, 30, 90, 190, 330, 510, ...

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The product of 5 more than a number, and 4
Lyrx [107]

Answer:

x + 5 * 4


In this problem we have to transfer the expression from verbal to mathematical language. Which would be:

x + 5 * 4

"x" represents "a number"

"5 more than a number" is represented by "x + 5"

"the product of" is indicating a multiplication, which is represented by "*"



Hope it helped,


BioTeacher101

3 0
3 years ago
Read 2 more answers
What is 2,168.433 rounded to the nearest mile?
olga nikolaevna [1]

Answer:

Suggestion 13 is a correction of the Constitution of California ordered during 1978, through the drive interaction. The drive was endorsed by California electors on June 6, 1978. It was maintained as established by the US High Court on account of Nordlinger v. Hahn, 505 U.S. 1.Proposition 13 is an amendment of the Constitution of California enacted during 1978, by means of the initiative process. The initiative was approved by California voters on June 6, 1978. It was upheld as constitutional by the United States Supreme Court in the case of Nordlinger v. Hahn, 505 U.S. 1.

8 0
2 years ago
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The radius of the base of a cylinder is 10 centimeters, and its height is 20 centimeters. A cone is used to fill the cylinder wi
klasskru [66]

The number of times one needs to use the completely filled cone to completely fill the cylinder with water is <u>24</u>.

In the question, we are given that the radius of the base of a cylinder is 10 centimeters, and its height is 20 centimeters. A cone is used to fill the cylinder with water. The radius of the cone's base is 5 centimeters, and its height is 10 centimeters.

We are asked to find the number of times one needs to use the completely filled cone to completely fill the cylinder with water.

The volume of a cylinder is calculated using the formula, V = πr²h.

The volume of a cone is calculated using the formula, V = (1/3)πr²h.

In both the formulas r is the radius and h is the height.

The volume of the given cylinder using the formula is π(10)²(20) cm³ = 2000π cm³.

The volume of the given cone using the formula is (1/3)π(5)²(10) cm³ = (250/3)π cm².

The number of times one needs to use the completely filled cone to completely fill the cylinder with water =

The volume of the given cylinder/The volume of the given cone,

or, The number of times one needs to use the completely filled cone to completely fill the cylinder with water = {2000π cm³}/{(250/3)π cm²},

or, The number of times one needs to use the completely filled cone to completely fill the cylinder with water = 24.

Thus, the number of times one needs to use the completely filled cone to completely fill the cylinder with water is <u>24</u>.

Learn more about the volume of a cylinder and cone at

brainly.com/question/26263468

#SPJ9

8 0
1 year ago
Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
2 years ago
What is the surface area of a triangular pyramid if each face has an area of 30 mm2?
coldgirl [10]
The answer must be 120\quad m{ m }^{ 2 } since the triangular pyramid has 4 faces and each has an area of 30 m{ m }^{ 2 } we should multiply that by 4 , so :

4\cdot 30\quad m{ m }^{ 2 }=\quad 120\quad m{ m }^{ 2 }
7 0
3 years ago
Read 2 more answers
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