Answer: The answer would be 8.5 times 10^-5
Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the
10 If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.
Answer:
Step-by-step explanation:
(4 cups)/(¼ cup) = 16
You need to use 16 of the ¼-cup measures.
To solve this, we need to find the LCM (Least Common Multiple) for 3 and 4 to have common denominator. 3 x 4 is 12.
So let us keep in mind 1 in this case is 12/12, and 2 is 24/12
2 of 2 1/3 is 24/12.
Let us find out 1/3
12 divided by 3 is 4, so we multiply both sides by 4.
1/3 x 4/4 is 4/12. 4/12 plus 24/12 is 28/12 equaling 2 and 4/12, or , if you simplified, 2 and 1/3
Now to find 1 and 3/4
1 is 12/12, and the easiest way to find 3/4 is to do 1/4 x 3 or 4/4 - 1/4. (I'm doing the first way)
12 divided by 4 is 3. we times both sides by 3. 1/4 x 3/3 = 3/12. since 3/4 is 1/4 x 3/1, we multiply 3/12 by 3/1, which equals 9/12.
1 (12/12) plus 3/4 (9/12) equals 21/12, or 1 and 3/4 simplified
Now we add 2 1/3 (28/12) by 1 3/4 (21/12) , we get 4 and 1/12 (simplest form/simplified) or 49/12
Answer is 49/12 or 4 and 1/2
:)
<h3>Answer is -9</h3>
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Work Shown:
(g°h)(x) is the same as g(h(x))
So, (g°h)(0) = g(h(0))
Effectively h(x) is the input to g(x). Let's first find h(0)
h(x) = x^2+3
h(0) = 0^2+3
h(0) = 3
So g(h(x)) becomes g(h(0)) after we replace x with 0, then it updates to g(3) when we replace h(0) with 3.
Now let's find g(3)
g(x) = -3x
g(3) = -3*3
g(3) = -9
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alternatively, you can plug h(x) algebraically into the g(x) function
g(x) = -3x
g( h(x) ) = -3*( h(x) ) ... replace all x terms with h(x)
g( h(x) ) = -3*(x^2 + 3) ... replace h(x) on right side with x^2+3
g( h(x) ) = -3x^2 - 9
Next we can plug in x = 0
g( h(0) ) = -3(0)^2 - 9
g( h(0) ) = -9
we get the same result.
12/6 you have to put it on top and bottom then subtract
