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Reptile [31]
3 years ago
15

Help me on this problems

Mathematics
1 answer:
elena55 [62]3 years ago
6 0
The answer for your problem (1) is 7.41
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Find the perimeter of the figure. (Will mark brainliest of correct!)
Lisa [10]

Answer:

24 inches.

Step-by-step explanation:

Add em' all up cuz.

6 0
3 years ago
Read 2 more answers
A Galapagos cactus finch population increases by half every decade. The number of finches is
Angelina_Jolie [31]

Answer:

The number of fringes at d=-2 is given as 20.

Step-by-step explanation:

Question

A Galapagos cactus finch population increases by half every decade. The number of finches is modeled by the expression

,

where d is the number of decades after the population was measured. Evaluate the expression for d = −2

Given :

The number of  finches is modeled by the expression  :

⇒ 45\cdot1.5^d

where d is the number of decades after the population was measured.

To evaluate the expression for d=-2

Solution:

In order to evaluate the given expression to find the number of finches at d=-2, we will plugin -2 for d in the expression and simplify it.

Plugging in d=-2 in the expression:

⇒ 45\cdot 1.5^{-2}

Using negative exponent property. [a^{-x}=\frac{1}{a^x}

⇒ 45\cdot \frac{1}{1.5^2}

⇒ 45\cdot \frac{1}{2.25}

⇒ 20   (Answer)

Thus, the number of fringes at d=-2 is given as 20.

This means the number of fringes two decades ago was 20.

6 0
3 years ago
Write the slope-intercept form of the equation of the line described. Do not include any spaces.
aliya0001 [1]
I am working on it...
8 0
2 years ago
If the point (3, 10) is on f(x), which point will be on f(x)+3?<br><br> please help me :(
Vinil7 [7]

Answer:

(3,13)

Step-by-step explanation:

so, you would add 3 to the y value

the point would be (3,13)

5 0
3 years ago
Calculate the frequency in hertz of photons of light with energy of 8.10 × 10-19 J.
stira [4]
The Planck–Einstein relation E=hv gives that E, the photon energy, is equal to h, Planck's constant, times <span>ν</span>, the frequency.

We can solve the equation in terms of frequency to get
v= \dfrac{E}{h}

We substitute our given energy, 8.10 \times 10^{-19} J, and Planck's constant, 6.626 \times 10^{-34} Js.

v= \dfrac{8.10 \times 10^{-19} J}{6.626 \times 10^{-34} Js}=1.22 \times 10^{15} s^{-1}=1.22 \times 10^{15} Hz
5 0
3 years ago
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