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Rama09 [41]
3 years ago
7

BAD is congruent to BCD by the

Mathematics
1 answer:
scoundrel [369]3 years ago
6 0
AB is congruent to BC
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If f={ (1,2),(3,5),(4,1)} and g= { (2,3), (5,1),(1,3)} , then (gof)=?
guapka [62]
<h3>Answer: Choice (b)</h3><h3>{ (1, 3),  (3, 1),  (4, 3) }</h3>

==================================================

Work Shown:

The notation "g o f" means g(f(x)). We have f(x) as the inner function that is computed first.

f(x) = {  (1,2),  (3,5), (4,1) }

The x coordinates of each point are: 1, 3, 4

The y coordinates are: 2, 5, 1

So the input x = 1 goes to y = 2 as the output. That output becomes the input of the g(x) function. Using x = 2 as the input for g, we see that 3 is the output. Check out the diagram below to see how each input goes into f, then goes into g to ultimately determine the x,y pairs. So far we've shown that x = 1 ultimately leads to y = 3.

Let's do another input: if x = 3 is plugged into f(x), then the output is 5 because of the point (3,5). Then x = 5 is plugged into g(x) to get x = 5 lead to y = 1. Ultimately x = 3 leads to y = 1 giving us (3,1) as another point.

Lastly, if x = 4 is plugged into f we get y = 1 as an output, which in turn is plugged into g to get 3 as the final output. The point (4,3) is the last ordered pair.

Again there's a lot to keep track of, so it helps to have a diagram as shown below.

4 0
3 years ago
Read 2 more answers
Use the properties of exponents to rewrite the expression <br> (-3yz)(-3yz)(-3yz)(-3yz)
Ipatiy [6.2K]

\bf (-3yz)(-3yz)(-3yz)(-3yz)\implies (-3yz)^1(-3yz)^1(-3yz)^1(-3yz)^1 \\\\\\ (-3yz)^{1+1+1+1}\implies (-3yz)^4\implies (-3)^4 y^4 z^4\implies 81y^4 z^4

8 0
3 years ago
What is the average rate of change from x=0 to x=5
zmey [24]
80-40/5-0=40/5=8 through the slope formula
6 0
3 years ago
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The line 3x-8y=k cuts the x-axis and y- axis at the point A and B respectively. If the area of ∆AOB =12sq.units, find the value
Sladkaya [172]

Given:

The equation is:

3x-8y=k

It cuts the x-axis and y- axis at the point A and B respectively.

The area of ∆AOB =12 sq.units.

To find:

The value of <em>k</em>.

Solution:

We have,

3x-8y=k

Substituting x=0 to find the y-intercept.

3(0)-8y=k

0-8y=k

y=\dfrac{k}{-8}

y=-\dfrac{k}{8}

Substituting y=0 to find the x-intercept.

3x-8(0)=k

3x-0=k

x=\dfrac{k}{3}

Area of a triangle is:

A=\dfrac{1}{2}\times base\times height

The height of the ∆AOB is OB=\dfrac{k}{8} because distance cannot be negative and the base of the ∆AOB is OA=\dfrac{k}{3}. So, the area of the ∆AOB is:

A=\dfrac{1}{2}\times \dfrac{k}{8}\times \dfrac{k}{3}

A=\dfrac{k^2}{48}

It is given that, the area of ∆AOB = 12 sq.units.

\dfrac{k^2}{48}=12

k^2=576

k=\pm \sqrt{576}

k=\pm 24

Therefore, the value of k is either 24 or -24.

4 0
3 years ago
The slope of the graph of y=-7 is____
Darina [25.2K]

Answer:

0

Step-by-step explanation:

y=mx+b

m = slope

we have y=-7

y = 0*x-7

m=0

y=-7

3 0
3 years ago
Read 2 more answers
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