3 years ago

BAD is congruent to BCD by the

1 answer:

6 0

AB is congruent to BC

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ale4655 [162]

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Effectus [21]

Answer:

Step-by-step explanation:

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66 squares are in the circle.

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elena55 [62]

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3 years ago

Genrish500 [490]

Answer:

Answer: The answer is option B.

Step-by-step explanation:

Here,

We have,

${ \sin }^{2} theta \: + {cos}^{2}theta = 1$

${cos}^{2} \: theta = 1 - {sin}^{2} \: theta$

$cos \: theta = \sqrt{1 - { \sin }^{2}theta }$

So, it's true; and it lies in quadrant 1 and 4.

The reason according to the "CAST" rule cos theta is in 1st and 3rd quadrant cos theta is positive.

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3 years ago