Answer:
missing info my dude
Step-by-step explanation:
Given the function f(x)=x^2+5x+5 , to get the zeros we solve using quadratic formula;
x=[-b(+or-) sqrt(b^2-4ac)]/(2a)
from our function;
a=1,b=5, c=5
thus,
x=[-5(+or-)sqrt(5^2-4*1*5)]/(2*1)
x=[-5(+or-)sqrt(25-20)]/2
x=[-5+/-sqrt(5)/2
The answer is option C
Then c = 22 just keep adding 7
8+7=15 15+7=22
Answer:
sin0 = -12
Step-by-step explanation:
tan0 = sin/cos
12/5 = sin / -15/3
sin = tan0 x cos0 = 12/5 x -15/3 = -12
