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Mariana [72]
3 years ago
8

Larry pays $60.75 for a golf club that was discounted by 25%. What was the price of the golf club before the discount?

Mathematics
1 answer:
USPshnik [31]3 years ago
5 0
The price before the discount was $81.00

Given;
Discounted price = $60.75
discount rate = 25%

Since the price is already discounted, it means that it is already 75% of the original price. So, we divided the discounted price by its corresponding percentage.

Original price - discount = discounted price
100% - 25% = 75%

$60.75 ÷ 75 % = $81.00 

$81.00 * 25% = 20.25 discount
$81.00 - 20.25 = 60.75 discounted price


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Answer:

Step-by-step explanation:

S(60/100)=159

60S=15900

S=265

So there are 265 total students.

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Simplify (23)^–2 genuinely confused
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1/529

Step-by-step explanation:

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Which determinants can be used to solve for x and y in the system of linear equations below?
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The right answer is the first answer

Step-by-step explanation:

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The sum of three numbers is 102. The first number is 6 more than the second. The third number is 4 times the second. What are th
const2013 [10]

Answer:

1st number: 22

2nd number: 16

3rd number: 64

Step-by-step explanation:

x + y + z = 102

x = 6 + y

z = 4y

plug that in!

(6 + y) + y + (4y) = 102

get rid of the parenthesis (I added them so you could see what I was replacing) and add like terms.

6 + 6y = 102

move 6 to the other side.

6y = 96

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now that you know one number, you can solve the equations for the rest!

x = 6 + (16)

z = 4(16)

__________________________________________________________

x = 22

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6 0
2 years ago
I dont understand this
Westkost [7]

Answer:

\dfrac{1}{2x(x-1)}

Step-by-step explanation:

Given

\dfrac{x^2+2x+1}{x^2-1}\div (2x^2+2x)

Consider the numerator:

x^2+2x+1=(x+1)^2

Consider the denominator:

x^2-1=(x-1)(x+1)

Hence, the fraction becomes

\dfrac{(x+1)^2}{(x-1)(x+1)}=\dfrac{x+1}{x-1}

Consider the expression in brackets:

2x^2+2x=2x(x+1)

Divide:

\dfrac{x^2+2x+1}{x^2-1}\div (2x^2+2x)=\dfrac{x+1}{x-1}\div 2x(x+1)=\dfrac{x+1}{x-1}\times \dfrac{1}{2x(x+1)}=\dfrac{1}{2x(x-1)}

4 0
3 years ago
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