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3 years ago

13

The selling price of a shirt before sales tax 10$.the finial price of a shirt including sales tax is 12.5 .what is the rate of t

he sales tax applied

1 answer:

maw [93]3 years ago

7 0

$11.25 because 10 times 1.125 is equal to 11.25

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Alaska has a land area of about 1700000 square miles Florida has a land area one tenth of the size of Alaska what is the land ar

AnnyKZ [126]

Answer:

The land area of Florida is $170,000\ mi^2$

Step-by-step explanation:

Let

x -----> the land area of Alaska in square miles

y -----> the land area of Florida in square miles

we know that

The linear equation that represent this problem is equal to

$y=\frac{1}{10}x$ ----> equation A

$x=1,700,000$ ----> equation B

substitute equation B in equation A and solve for y

$y=\frac{1}{10}(1,700,000)=170,000\ mi^2$

Remember that

Florida's land area is one-tenth the size of Alaska is the same as to say that Alaska's land area is ten times the size of Florida

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3 years ago

Determine the slopes from the given information<br><br> A line through (3,-3) and (8,4)

Helga [31]

The answer should be 7/5

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2 years ago

Please help me. My homework is due at 11:59

siniylev [52]

The grocery store selling a 3 pound bag for $4.20. while the other store would sell it for $4.50.

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3 years ago

Read 2 more answers

Order of operations how do you solve 10/5*(7-2+4^2)

kvv77 [185]

10/5 =2
7-2+4^2 =5+16=21
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3 0

3 years ago

Jason and Alison are hiking in the woods when they spot a rare owl in a tree. Jason stops and measures an angle of elevation of

Shalnov [3]

Answer:

$Owl= 67.14ft$

Step-by-step explanation:

<em>See comment for complete question.</em>

The given information is represented in the attached figure.

First convert 22°8'6'' and 30° 40’ 30” to degrees

$22^{\circ} 8'6'' = 22 + \frac{8}{60} + \frac{6}{3600}$

$22^{\circ} 8'6'' = 22.135^{\circ}$

$30^{\circ} 40'30'' = 30 + \frac{40}{60} + \frac{30}{3600}$

$30^{\circ} 40'30'' = 30.675^{\circ}$

Considering Jason's position:

$tan(22.135^{\circ}) = \frac{H}{x + 48}$

Where x = distance between the tree and Alison

Make H the subject

$H = (x + 48)tan(22.135^{\circ})$

Considering Alison's position

$tan(30.675^{\circ}) = \frac{H}{x}$

Make H the subject

$H = xtan(30.675^{\circ})$

$H = H$

$(x + 48)tan(22.135^{\circ}) = xtan(30.675^{\circ})$

$(x + 48) *0.4068 = x* 0.5932$

Open bracket

$x *0.4068 + 48 *0.4068 = 0.5932x$

$0.4068x + 19.5264 = 0.5932x$

Collect Like Terms

$-0.5932x+0.4068x = -19.5264$

$-0.1864x = -19.5264$

$0.1864x = 19.5264$

Make x the subject

$x = \frac{19.5264}{0.1864}$

$x = 104.76$

Substitute 104.76 for x in $H = xtan(30.675^{\circ})$

$H = 104.76 * tan(30.675^{\circ})$

$H = 104.76 * 0.5932$

$H = 62.14$

The above represents the height of the tree.

The height of the owl is:

$Owl= H + 5$

$Owl= 62.14 + 5$

$Owl= 67.14ft$

7 0

2 years ago