You have a %0.01 chance of winning. Good luck.
Calculate the probability that both bids are successful
Answer:
The probability that both contracs are successful is 0.21
Step-by-step explanation:
Given
E1 = the event that the bid on the first contract is successful
E2 = the event that the bid on the second contract is successful
P(E1) = 0.3
P(E2) = 0.7
Let P(A) represent the event that both contracts are successful
P(A) = P(E1 and E2)
Since both events are independent. P(A) becomes
P(A) = = P(E1 * P(E2)
By substituton
P(A) = 0.3 * 0.7
P(A) = 0.21
Hence the probability that both contracs are successful is 0.21
Angle 2 = 22 degrees (that line is dividing that angle into 1 & 2 equivalently)
Angle 3 = 90 degrees.
Step-by-step explanation:
In the second step while opening the bracket, instead of 'a', there should be - 4a.
Assuming we’re talking about a cylinder, whose volume formula is V = pi r^2 h…
It will have a greater effect to change a variable’s value that has a greater power on it.
Changing h from 1 to 2 doubles the volume.
Changing r from 1 to 4 quadruples the volume, because 1^2 = 1 and 2^2 = 4. The effect of the change on r is amplified by the power.
