Train A and train B leave a central station at the same time. They travel the same speed, but in opposite directions, with train A heading towards station A, and train B heading towards station B. Train A reaches station A after 4 h. Train B reaches station B after 312 h. Station A and Station B are 562.5 mi apart.
2 answers:
Answer: speed = 585/(13/2) = 90 miles per hour.
Step-by-step explanation:speed = distance / time
since they are moving in opposite direction, the time is the sum of the two times = 2 1/2 + 4 = 6 1/2 = 13/2
Divide the total distance by 2, to get the miles each train traveled.
562.5 / 2 = 281.25 miles.
Train A traveled for 4 hours:
281.25 miles / 4 hours = 70.3125 miles per hour.
Train B traveled for 3 1/2 hours:
281.25 miles / 3 1/2 hours = 80.357 miles per hour.
Round the speed of each train as needed.
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Answer:
Step-by-step explanation:
19*19=361.
Solve for e
d = 1/e + 1/f
Move 1/f to the left side of the = sign
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Multiply each side by e
e(d - 1/f) = e(1/e)
e(d - 1/f) = 1
Divide out (d - 1/f)
e(d - 1/f) / (d - 1/f) = 1 / (d - 1/f)
e = 1 / (d - 1/f)
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