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ruslelena [56]
3 years ago
9

Train A and train B leave a central station at the same time. They travel the same speed, but in opposite directions, with train

A heading towards station A, and train B heading towards station B. Train A reaches station A after 4 h. Train B reaches station B after 312 h. Station A and Station B are 562.5 mi apart.
What is the rate of the trains?
Mathematics
2 answers:
ira [324]3 years ago
8 0

Answer: speed = 585/(13/2) = 90 miles per hour.

Step-by-step explanation:speed = distance / time

since they are moving in opposite direction, the time is the sum of the two times = 2 1/2 + 4 = 6 1/2 = 13/2

PtichkaEL [24]3 years ago
5 0

Divide the total distance by 2, to get the miles each train traveled.

562.5 / 2 = 281.25 miles.

Train A traveled for 4 hours:

281.25 miles / 4 hours = 70.3125 miles per hour.

Train B traveled for 3 1/2 hours:

281.25 miles / 3 1/2 hours = 80.357 miles per hour.

Round the speed of each train as needed.

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At a baseball game, a hamburger costs $2 more than
Aliun [14]

Answer:

Hamburger = $6

Hotdog = $4

Step-by-step explanation:

136 - 14(2) = 108

108 / 13 + 14 = 4

If a hamburger is 2 dollars more than you would just add 2 to this

4 0
3 years ago
A shopkeeper has 2,625 markers. He would like to pack 25 markers in each box. How many boxes will he need?
Lerok [7]

Answer:

it's 105 boxes.

Step-by-step explanation:

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5 0
3 years ago
PLEASE PEOPLE, HELP ME!! Geometry
Oksanka [162]
I use the sin rule to find the area

A=(1/2)a*b*sin(∡ab)

1) A=(1/2)*(AB)*(BC)*sin(∡B)
sin(∡B)=[2*A]/[(AB)*(BC)]

we know that
A=5√3
BC=4
AB=5
then

sin(∡B)=[2*5√3]/[(5)*(4)]=10√3/20=√3/2
(∡B)=arc sin (√3/2)= 60°

 now i use the the Law of Cosines 

c2 = a2 + b2 − 2ab cos(C)

AC²=AB²+BC²-2AB*BC*cos (∡B)

AC²=5²+4²-2*(5)*(4)*cos (60)----------- > 25+16-40*(1/2)=21

AC=√21= 4.58 cms

the answer part 1) is 4.58 cms

2) we know that

a/sinA=b/sin B=c/sinC

and

∡K=α

∡M=β

ME=b

then

b/sin(α)=KE/sin(β)=KM/sin(180-(α+β))

KE=b*sin(β)/sin(α)

A=(1/2)*(ME)*(KE)*sin(180-(α+β))

sin(180-(α+β))=sin(α+β)

A=(1/2)*(b)*(b*sin(β)/sin(α))*sin(α+β)=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

KE/sin(β)=KM/sin(180-(α+β))

KM=(KE/sin(β))*sin(180-(α+β))--------- > KM=(KE/sin(β))*sin(α+β)

the answers part 2) are

side KE=b*sin(β)/sin(α)
side KM=(KE/sin(β))*sin(α+β)
Area A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

5 0
3 years ago
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