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ruslelena [56]
4 years ago
9

Train A and train B leave a central station at the same time. They travel the same speed, but in opposite directions, with train

A heading towards station A, and train B heading towards station B. Train A reaches station A after 4 h. Train B reaches station B after 312 h. Station A and Station B are 562.5 mi apart.
What is the rate of the trains?
Mathematics
2 answers:
ira [324]4 years ago
8 0

Answer: speed = 585/(13/2) = 90 miles per hour.

Step-by-step explanation:speed = distance / time

since they are moving in opposite direction, the time is the sum of the two times = 2 1/2 + 4 = 6 1/2 = 13/2

PtichkaEL [24]4 years ago
5 0

Divide the total distance by 2, to get the miles each train traveled.

562.5 / 2 = 281.25 miles.

Train A traveled for 4 hours:

281.25 miles / 4 hours = 70.3125 miles per hour.

Train B traveled for 3 1/2 hours:

281.25 miles / 3 1/2 hours = 80.357 miles per hour.

Round the speed of each train as needed.

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Finger [1]

Answer:

<h3>34.61</h3>

Step-by-step explanation:

Find the diagram attached

From the diagram;

Hypotenuse = 81.9

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Required

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Using the SOH CAH TOA identity

cos theta = adjacent/Hypotenuse

cos 65 = x/81.9

x = 81.9cos65

x = 81.9(0.4226)

x = 34.61

Hence the value of x to the nearest hundredth is 34.61

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