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3 years ago

Is circle Tangent lines

Mathematics

1 answer:

Sergio [31]3 years ago

4 0

no because it is not a right angled triangle.

this means angle A is not 90° so AB cant be a tangent.

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Make x the subject in the relation

tatyana61 [14]

Cant read your writing-

7 0

2 years ago

A quadratic equation that can be written as the difference of squares has...

quester [9]

Answer: C two solutions

Step-by-step explanation:

The Difference of Two Squares theorem says that any time an equation may be written as a difference between squares A² - B² = 0 it may be rewritten as two products, the sum and difference of the square roots (A + B) (A - B)

Hope this helped :)

6 0

2 years ago

Read 2 more answers

What is the remainder when the polynomial f(x) = x³ - x² + 3x - 2, is divided by 2x - 1

Contact [7]

Answer:

Equate the divisor to 0

2x-1=0

2×=1

×=1/2

Putting onto the polynomial

f(1/2) = (1/2)³-1/2)²+3(1/2)-2

=-5/8

8 0

2 years ago

Semicircles

Studentka2010 [4]

Answer:

The area of the shaded portion of the figure is $9.1\ cm^2$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The shaded area is equal to the area of the square less the area not shaded.

There are 4 "not shaded" regions.

step 1

Find the area of square ABCD

The area of square is equal to

$A=b^2$

where

b is the length side of the square

we have

$b=4\ cm$

substitute

$A=4^2=16\ cm^2$

step 2

We can find the area of 2 "not shaded" regions by calculating the area of the square less two semi-circles (one circle):

The area of circle is equal to

$A=\pi r^{2}$

The diameter of the circle is equal to the length side of the square

$r=\frac{b}{2}=\frac{4}{2}=2\ cm$ ---> radius is half the diameter

substitute

$A=\pi (2)^{2}$

$A=4\pi\ cm^2$

Therefore, the area of 2 "not-shaded" regions is:

$A=(16-4\pi) \ cm^2$

and the area of 4 "not-shaded" regions is:

$A=2(16-4\pi)=(32-8\pi)\ cm^2$

step 3

Find the area of the shaded region

Remember that the area of the shaded region is the area of the square less 4 "not shaded" regions:

$A=16-(32-8\pi)=(8\pi-16)\ cm^2$

---> exact value

assume

$\pi =3.14$

substitute

$A=(8(3.14)-16)=9.1\ cm^2$

8 0

3 years ago

Solve the equation

inysia [295]

Answer:

x ≈ 1.32, x ≈ - 5.32

Step-by-step explanation:

Given

x² + 4x - 7 = 0 ( add 7 to both sides )

x² + 4x = 7

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(2)x + 4 = 7 + 4

(x + 2)² = 11 ( take the square root of both sides )

x + 2 = ± $\sqrt11}$ ( subtract 2 from both sides )

x = - 2 ± $\sqrt{11}$

Thus

x = - 2 - $\sqrt{11}$ ≈ - 5.32 ( to 2 dec. places )

x = - 2 + $\sqrt{11}$ ≈ 1.32 ( to 2 dec. places )

8 0

2 years ago

Read 2 more answers