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4 years ago

12

A circular playground for a daycare center is to be covered with square tiles that are 9 inches on each side. The circle has a d

iameter of 12 ft. The tiles are packaged in boxes of 25 tiles. How many boxes of tiles are needed?
A. 6 (not A)
B. 8
C. 9
D. 12

2 answers:

xxTIMURxx [149]4 years ago

3 0

The answer should be B. not sure on this one

Zanzabum4 years ago

3 0

Answer:

c

Step-by-step explanation:

ya it is c

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Every person has blood type O, A, B, or AB. A random group of people are blood-typed, and the results are shown in the table.

vova2212 [387]

The probability that a randomly chosen person from this group has type B is <u>3/25</u>

The probability that a randomly chosen person from this group has type AB is <u>1/25</u>

The probability that a randomly chosen person from this group has type B or type AB blood is <u>4/25</u>

8 0

3 years ago

Read 2 more answers

Wat r partial products of 452×12

Dennis_Churaev [7]

400×10=4000
400×2=800
50×10=500
50×2=100
2×10=20
2×2=4

4000+800+500+100+20+4=5,424
Check answer by multiplying 452 and 12
452×12=5,424

5 0

3 years ago

Idk wby it sets it up so weird in word form so imma just put this here

Anit [1.1K]

Answer:

141/2, 279/4

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

How to Find x value: 9-0.75(x+8)-5=-6.5

Dahasolnce [82]

Here's how to find the value of x:

<span>9 - 0.75 ( x + 8 ) - 5 = -6.5 find the difference of 9 - 0.75

</span><span>8.25 ( x + 8 ) - 5 = -6.5 add 5 to both sides
</span>
8.25 ( x + 8 ) = -1.5 distribute 8.25 to x and 8

8.25x + 66 = -1.5 subtract 66 from both sides

8.25x = -67.5 divide both sides by 8.25

x = 18.18181818...... the value of x is 18 2/11

hope this helps

8 0

3 years ago

Find the derivative.

krek1111 [17]

Answer:

$\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

General Formulas and Concepts:

<u>Algebra I</u>

Terms/Coefficients

Expanding/Factoring

<u>Calculus</u>

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

$\displaystyle f(x) = \frac{\sqrt{x}}{e^x}$

<u>Step 2: Differentiate</u>

Derivative Rule [Quotient Rule]: $\displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}$
Basic Power Rule: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}$
Exponential Differentiation: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}$
Simplify: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}$
Rewrite: $\displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}$
Factor: $\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

3 years ago