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Finger [1]
3 years ago
12

A circular playground for a daycare center is to be covered with square tiles that are 9 inches on each side. The circle has a d

iameter of 12 ft. The tiles are packaged in boxes of 25 tiles. How many boxes of tiles are needed?
A. 6 (not A)
B. 8
C. 9
D. 12
Mathematics
2 answers:
xxTIMURxx [149]3 years ago
3 0
The answer should be B. not sure on this one
Zanzabum3 years ago
3 0

Answer:

c

Step-by-step explanation:

ya it is c


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What is the distance between (-3, 4) and (-3, 10)?
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6 is the the distance between the points

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2 years ago
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The formula for finding the perimeter of a rectangle is P = 2L + 2W. If a rectangle has a perimeter of 68 inches and the length
Artemon [7]

Answer:

Width = 10 inches

Step-by-step explanation:

Given the perimeter of a rectangle of 68 inches, and a length that is 14 inches longer than its width.

We can establish the following values to help us solve for the width of a rectangle:

Perimeter (P) = 68 inches

Length (L) = 14 + W inches

Width (W) = unknown

<h3 /><h3><u>Solve for the Width (W)</u></h3>

P =  2(L + W)  ⇒ This is the same as P = 2L + 2W, except that 2 is factored out from the right-hand side.

Divide both sides by 2:

\displaystyle\mathsf{\frac{P}{2}\:=\:\frac{2(L\:+\:W)}{2}}

\displaystyle\mathsf{\frac{P}{2}\:=L\:+\:W}

Substitute the value of the Perimeter and the length (L) into the formula:

\displaystyle\mathsf{\frac{68}{2}\:=14\:+W\:+\:W}

Combine like terms on the right-hand side, and simplify the left-hand side of the equation:

\displaystyle\mathsf{34\:=14\:+2W}

Subtract 14 from both sides:

34 - 14 = 14 - 14 + 2W

20 = 2W

Divide both sides by 2 to solve for the width (W):

\displaystyle\mathsf{\frac{20}{2}\:=\:\frac{2W}{2}}

W = 10 inches

Therefore, the width of the rectangle is 10 inches.

<h3 /><h3><u>Double-check:</u></h3>

Verify whether the derived value for the width is correct:

P = 2L + 2W

68 = 2(14 + 10) + 2(10)

68 = 2(34) + 20

68 = 48 + 20

68 = 68 (True statement).  

Thus, the length of the rectangle is 34 inches, and the width is 10 inches.

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