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4 years ago

Eric traveled 6 miles in 15 minutes. Find the rate of speed.

Mathematics

1 answer:

Anton [14]4 years ago

3 0

Answer:2.5

Step-by-step explanation: just do 6 divided by 15 and the rate is 2.5

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(PLEASE HELP ME ASAP‼️)

tia_tia [17]

Answer:

Step-by-step explanation:

I really can't give you a step-by-step

7 0

3 years ago

If XYZ measures 45°, what is the measure of ?

ololo11 [35]

D. 45 and can you answer my history please ASAP

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3 years ago

Solve for the indicated variable. Include all of your work in your answer. Submit your solution. P = 3r + 2s; for s.

madam [21]

<h3>Given</h3>

P = 3r + 2s

the corresponding equation for s

<h3>Solution</h3>

First of all, look at how this is evaluated in terms of what happens to a value for s.

s is multiplied by 2
3r is added to that product

To solve for s, you undo these operations in reverse order. The "undo" for addition is adding the opposite. The "undo" for multiplication is division (or multiplication by the reciprocal).

... P = 3r + 2s . . . . . . starting equation

... P - 3r = 2s . . . . . . -3r is added to both sides to undo addition of 3r

... (P -3r)/2 = s . . . . . both sides are divided by 2 to undo the multiplication

Note that the division is of everything on both sides of the equation. That is why we need to add parentheses around the expression that was on the left—so the whole thing gets divided by 2.

Your solution is ...

... s = (P - 3r)/2

3 0

3 years ago

Let log_(b)A=3; log_(b)C=2; log_(b)D=5 what is the value of log_(b)((A^(5)C^(2))/(D^(6)))

Colt1911 [192]

Answer:

-11

Step-by-step explanation:

Given

$\log_bA=3\\ \\\log_bC=2\\ \\\log_bD=5$

Use properties:

$\log_b(A\cdot C)=\log_bA+\log_bC\\ \\\log_b\dfrac{A}{C}=\log_bA-\log_bC\\ \\\log_bA^k=k\log_bA$

Thus,

$\log_b\dfrac{A^5\cdot C^2}{D^6}\\ \\=\log_b(A^5\cdot C^2)-\log_bD^6\\ \\=\log_bA^5+\log_bC^2-\log_bD^6\\ \\=5\log_bA+2\log_bC-6\log_bD\\ \\=5\cdot 3+2\cdot 2-6\cdot 5\\ \\=15+4-30\\ \\=-11$

3 0

3 years ago

Is the open sentence 3z=2z+5 true or false when z=5?<br><br> A. True<br> B. False

inna [77]

Hey there!

If z = 5

we replace "z" with "5"

So, let's test out the problem to see if it is true or false

Problem becomes: $3(5) = 2(5) + 5$

Let's work this out

$3(5) = 15$

Problem becomes: $15 = 2(5) + 5$

$2(5) = 10$

Problem becomes: $15 = 10 + 5$

$10 + 5 = 15$

So, therefore it looks like this statement/ sentence is $True$ !

~ $MeIsKaitlyn:)$

3 0

3 years ago