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lara31 [8.8K]
3 years ago
15

Solve the following equation using the methods learned in this section. 3a2 = 54

Mathematics
1 answer:
MrRissso [65]3 years ago
7 0

The answer is a = 3√2. The explanation and steps of how I got the answer is in the image below.

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A recently discovered planet rotates 250 times on its axis in 15 months. At this rate, how many times will the planet rotate in
Stella [2.4K]

Answer:

H:150

Step-by-step explanation:

you divide 250 by 15 to get the amount of rotations per month, then once you get that answer which is 16.6666667, you then multiply that number by 9 and there is your answer

6 0
3 years ago
Which expressions form an equation with the given expression?
kolezko [41]
Numbers 2, 4 and 5 are the correct answers.
Hope this helps!
8 0
3 years ago
Please help! A-level maths.
astra-53 [7]

x+y=k\implies y=k-x

Substitute this into the parabolic equation,

k-x=6-(x-3)^2\implies x^2-7x+(k+3)=0

We're told the line x+y=k intersects C twice, which means the quadratic above has two distinct real solutions. Its discriminant must then be positive, so we know

(-7)^2-4(k+3)=49-4(k+3)>0\implies k

We can tell from the quadratic equation that C has its vertex at the point (3, 6). Also, note that

-1\le\sin t\le1\implies3\le3+2\sin t\le5\implies3\le x\le5

and

-1\le\cos2t\le1\implies2\le4+2\cos2t\le6\implies2\le y\le6

so the furthest to the right that C extends is the point (5, 2). The line x+y=k passes through this point for 2+5=k\implies k=7. For any value of k, the line x+y=k passes through C either only once, or not at all.

So 7\le k; in set notation,

\{k\mid 7\le k

4 0
3 years ago
During which time period does Landon's elevation change the fastest? Explain how you know?
bogdanovich [222]
<h3>1. How many inches per minute does London's elevation change between 4 minutes and 8 minutes. </h3>

The question actually asks for the slope of the line that stands for the points (4,3) \ and \ (8,6) why? because the questions tells us that London's elevation changes between 4 minutes and 8 minutes here. Hence, to find the slope of this line we have to use the following formula:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ But: \\ \\ P(x_{1},y_{1})=P(4,3) \\ P(x_{2},y_{2})=P(8,6)

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ But: \\ \\ P(x_{1},y_{1})=P(4,3) \\ P(x_{2},y_{2})=P(8,6) \\ \\ So: \\ \\ m=\frac{6-3}{8-4}=0.75in/min

<em>So London's elevation changes 0.75 inches per minute</em>

<em></em>

<h3>2. During which time period does London's elevation change the fastest?</h3>

The greater the absolute value of the slope of the line the faster London's elevation changes. Since this is a Piecewise function, we must analyze each period.

  • FIRST:

→ Between 0 minutes and 4 minutes the function is constant, so there is no any change here.

→ Between 10 minutes and 14 minutes the function is constant, so there is no any change here.

→ Between 18 minutes and 22 minutes the function is constant, so there is no any change here.

So the solution is not in these parts of the function.

  • SECOND:

→ Between 4 minutes and 10 minutes the function has a positive slope, so there is change here.

In the previous item we calculated the slope between 4 and 8 minutes that is the same slope between 4 and 8 minutes and equals 0.75.

→ Between 14 minutes and 18 minutes the function has a positive slope, so there is change here.

Let's take two points here, say, (16,5) \ and \ (18,3)

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ But: \\ \\ P(x_{1},y_{1})=P(16,5) \\ P(x_{2},y_{2})=P(18,3) \\ \\ So: \\ \\ m=\frac{3-5}{18-16}=-1 in/min

As you can see, the absolute value here is 1 that is greater than 0.75.

<em>In conclusion, London's elevation changes the fastest between 14 and 18 minutes</em>

7 0
3 years ago
➥ The base of a parallelogram is thrice its height. If the area is 897 sq.cm. Find the base and height of the parallelogram.
IgorC [24]

Answer:

The height of parallelogram is 51.87 cm

Step-by-step explanation:

Let The height of a parallelogram = a cm

Then

The base of a parallelogram = 3a cm

So by the given condition

3a×a = 897

3a^2 = 897

a^2 = 897/3

a^2 = 299

a = 17.29

So the height of parallelogram = 3×17.29= 51.87 cm

6 0
3 years ago
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