400+575+575+670+720+885+1250=5075
5075/7=725
Mean = 725
400, 575, 575, 670, 720, 885, 1250
Median = 670
725>670
C) The Mean is greater than the Median
Answer:
38 units.
Step-by-step explanation:
4x + 6 =
{midpoint theorem}
4x + 6 = 
4x + 6 = 2x + 22
4x -2x + 6 = 22
2x + 6 = 22
2x = 22 -6
2x = 16
x = 16/2
x = 8
Length of midsegment = 4x + 6 = 4*8 + 6
= 32 + 6
= 38
Unless you just want to give money to the ice cream truck, for 0 items, you will pay 0.
Since the price of each item is $0.77, for one item you will pay $0.77. (Is that a surprise?)
Then for two items, you will pay $0.77 for each one, or $0.77 + 0.77 = $1.54. You can also compute this by making use of the fact that multiplication is a shortcut for repeated addition. The price can be found by $0.77×2 = $1.54 = f(2).
Similarly, for 3 items, you can add $0.77 three times: $0.77 + 0.77 + 0.77 = f(3), or you can use multiplication: $0.77×3 = $2.31 = f(3).
a) Our table looks like
(x, f(x))
(0, 0)
(1, 0.77)
(2, 1.54)
(3, 2.31)
b) By now, I'm sure you have realized that to find the price of x items, you multiply 0.77 by x.
f(x) = 0.77x
Answer:
- 150π ft²
- 10π ft.
Step-by-step explanation:
Area of the sector :

Finding the area given r = 30 ft. and θ = 60° :
⇒ Area = π × (30)² × 60/360
⇒ Area = π × 900/6
⇒ Area = 150π ft²
===========================================================
Length of the arc :

Finding the arc length given r = 30 ft. and θ = 60° :
⇒ Arc Length = 2 × π × 30 × 60/360
⇒ Arc Length = 60/6 × π
⇒ Arc Length = 10π ft.
Answer:
It's the 2nd option 2*2*3*3*5
Step-by-step explanation: