Question

If the sum of four consecutive numbers is n, what is the first one?

Answer 1

$x - first\ number\\\\x,\ x+1,\ x+2,\ x+3-\text{four consecutive integers}\\\\\text{The equation:}\\\\x+(x+1)+(x+2)+(x+3)=n\\\\4x+6=n\ \ \ \ |-6\\\\4x=n-6\ \ \ \ \ |:4\\\\\boxed{x=\dfrac{n-6}{4}}$

$m, m+1,\ m+2,\ m+3,\ m+4,\ m+5,\ m+6-\text{seven consecutive numbers}\\\\\text{The sum}\\\\m+(m+1)+(m+2)+(m+3)+(m+4)+(m+5)+(m+6)=7m+21$