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stealth61 [152]
3 years ago
9

In a survey taken of 60 households, 40 households reported having a dog and 30 households reported having a cat. If half of all

households having a cat also have a dog, how many households reported have neither a dog nor a cat?
Mathematics
1 answer:
AfilCa [17]3 years ago
7 0
So, if 30 housholds have a cat 30/2 is 15.
15 housholds have a cat and a dog
30-15= 15 housholds have only cats
40-15=25 housholds only have dogs
25+15+15=55
60 housholds in total, so what is 60-55? <-- This will be your answer.
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Kobe,A’mari and DJ are raising money for the football team to take a trip to San Diego.kobe collected $24.55 more than A‘Mari, A
Novay_Z [31]

Answer:

DJ= $39.58

Step-by-step explanation:

KOBE (K)

DJ (DJ)

A'MARI (A)

K= $24.55 + A

DJ= K –$15.60

Total Amount= $125.40

(24.55 + A) + (K – 15.60 + A) + A= 125.40

2A + K + 8.95 = $125.40

2A + K = $116.45

2A + (24.55 + A) = $116.45

3A = $91.90

A= 91.90 ÷ 3

A= $30.63

Therefore,

K= 24.55 + 30.63

K= $55.18

DJ= $55.18 – 15.60

DJ= $39.58

8 0
2 years ago
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Step-by-step explanation:

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The pattern is - 8 so the answer is 12.
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Find the sum and express it in simplest form.<br><br> (-5y^3 - 7y) + (7y^3 + 8y +9)
Tema [17]
<span>(-5y^3 - 7y) + (7y^3 + 8y +9)
</span>

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Read it carefully as it may look confusing with the symbols. 
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