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stealth61 [152]
3 years ago
9

In a survey taken of 60 households, 40 households reported having a dog and 30 households reported having a cat. If half of all

households having a cat also have a dog, how many households reported have neither a dog nor a cat?
Mathematics
1 answer:
AfilCa [17]3 years ago
7 0
So, if 30 housholds have a cat 30/2 is 15.
15 housholds have a cat and a dog
30-15= 15 housholds have only cats
40-15=25 housholds only have dogs
25+15+15=55
60 housholds in total, so what is 60-55? <-- This will be your answer.
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Answer:

Step-by-step explanation:

\frac{-3+7i}{-6-7i} \times \frac{-6+7i}{-6+7i} =\frac{18-21i-42i-49i^2}{(-6)^2-(7i)^2} \\=\frac{18-63i -49(-1)}{36-49i^2} \\=\frac{18+49-63 i}{36-49(-1)} \\=\frac{67-63i}{36+49} \\=\frac{67-63i}{85} \\=\frac{67}{85} +(\frac{-63}{85} )i\\

a=\frac{67}{85} \\b=\frac{-63}{85}

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Hello!

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Hope this helped.
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