Question

If EF=9x+14, FG=56, and EG=250, find the value of x.

Answer 1

Well, assuming E is the beginning, F is the middle, and G is the end, then

9x+14+56=250
9x=250-(56+14)
9x=250-70
9x=180
9x/9=180/9
X=20

The whole E to G is 250, and it gave you lengths between it

Answer 2

Answer:

Value of x =20

Step-by-step explanation:

Given: EF = 9x+14 units , FG = 56 units and EG = 250 units.

Segment Addition Postulates states the following for 3 points that are collinear.

i.e, Let three points A, B and C are collinear and B is between A and C.

i,e AC = AB + BC

By Segment addition postulates; solve for x;

EG = EF + FG

Substitute the given values we get;

250 = 9x + 14 + 56

or

250 = 9x + 70

Subtract 70 on both sides we get;

250 -70 = 9x + 70 -70

Simplify:

180 = 9x

Divide both sides by 9 we get;

$\frac{180}{9} = \frac{9x}{9}$

Simplify:

x = 20

Therefore, the value of x =20