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3 years ago

Use the listing method to write the following set.

Mathematics

1 answer:

vampirchik [111]3 years ago

3 0

It’s C because it’s less than 3

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the library is located 1.8 miles west of callies house.the grocery store is located 2.4 miles south of the library what is the l

torisob [31]

Use Pythagaras theorem :-

x^2 = 1.8^2 + 2.4^2 where a is distance required

x^2 = 9

x = 3 miles Answer

8 0

3 years ago

Read 2 more answers

The perimeter of a rectangle is 46 in and the diagonal is 17 in. Find the area of the rectangle.

OlgaM077 [116]

P=2*(L+l)=46
L+l=46:2
L+l=23
(L+l)^2=529
(L^2+l^2)+2l*L=529

D= V L^2+l^2= 17
L^2+l^2=289

so 289+2l*L=529
2l*L=529-289=240
l*L=240:2
A=120

5 0

3 years ago

What is a correct equation for the line passing through the point (-2,1) and having slope m=1/2

frez [133]

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

We ahve the slope m = 1/2 and the point (-2, 1). Substitute:

$y-1=\dfrac{1}{2}(x-(-2))$

$y-1=\dfrac{1}{2}(x+2)$ - point-slope form

Covert to the slope-intercept form (y = mx + b):

$y-1=\dfrac{1}{2}(x+2)$ use the distributive property

$y-1=\dfrac{1}{2}x+1$ add 1 to both sides

$y=\dfrac{1}{2}x+2$ - slope-intercept form

Convert to the standard form (Ax + By = C):

$y=\dfrac{1}{2}x+2$ multiply both sides by 2

$2y=x+4$ subtract x from both sides

$-x+2y=4$ change the signs

$x-2y=-4$ - standard form

Convert to the general form (Ax+By+C=0):

$x-2y=-4$ add 4 to both sides

$x-2y+4=0$ - general form

5 0

3 years ago

Can you simplify 3k+8-k+72

Lelu [443]

Answer:

2k + 80

Step-by-step explanation:

Combine like terms.

3k + 8 - k + 72 =

= 3k - k + 8 + 72

= 2k + 80

4 0

3 years ago

Read 2 more answers

For the right triangles below, find the exact values of the side lengths a and c. If necessary, write your responses in simplifi

alex41 [277]

Answer:

First triangle: $a = 5\sqrt{2}$ , second triangle: $c = \frac{8\sqrt{3}}{3}$

Step-by-step explanation:

In the first triangle, the value of $a$ is equal to the following trigonometric relation:

$a = \frac{5}{\cos 45^{\circ}}$

$a = \frac{5}{\frac{\sqrt{2}}{2} }$

$a = \frac{10}{\sqrt{2}}$

$a = \frac{10\sqrt{2}}{2}$

$a = 5\sqrt{2}$

In the second triangle, we obtain the value of $c$ is equal to the following trigonometric relation:

$c = 8\cdot \tan 30^{\circ}$

$c = 8 \cdot \left(\frac{\sin 30^{\circ}}{\cos 30^{\circ}} \right)$

$c = 8\cdot \left(\frac{\frac{1}{2} }{\frac{\sqrt{3}}{2} } \right)$

$c = \frac{8}{\sqrt{3}}$

$c = \frac{8\sqrt{3}}{3}$

8 0

2 years ago