Given:
The right triangular prism.
Height of prism = 28 in.
Hypotenuse of base = 25 in.
leg of base = 24 in.
To find:
The lateral surface area of the prism.
Solution:
Pythagoras theorem:
![Hypotenuse^2=Perpendicular^2+Base^2](https://tex.z-dn.net/?f=Hypotenuse%5E2%3DPerpendicular%5E2%2BBase%5E2)
Using Pythagoras theorem in the base triangle, we get
![25^2=24^2+Base^2](https://tex.z-dn.net/?f=25%5E2%3D24%5E2%2BBase%5E2)
![625-576=Base^2](https://tex.z-dn.net/?f=625-576%3DBase%5E2)
![\sqrt{49}=Base](https://tex.z-dn.net/?f=%5Csqrt%7B49%7D%3DBase)
![7=Base](https://tex.z-dn.net/?f=7%3DBase)
The perimeter of the triangular base is:
![P=7+25+24](https://tex.z-dn.net/?f=P%3D7%2B25%2B24)
![P=56](https://tex.z-dn.net/?f=P%3D56)
Lateral area of a triangular prism is:
![A=Ph](https://tex.z-dn.net/?f=A%3DPh)
Where, P is the perimeter of the triangular base and h is the height of the prism.
Putting
in the above formula, we get
![A=56(28)](https://tex.z-dn.net/?f=A%3D56%2828%29)
![A=1568](https://tex.z-dn.net/?f=A%3D1568)
Therefore, the lateral area of the prism is 1568 in².
Find a number to will divide into both the numerator and denominator equally.
For example, take a look at this fraction: 10/15
What number can both divide evenly into the numerator and denominator? Well, 5!
10/15 / 5/5 = 2/3
Answer:
the answer of this question is " 1 "
Step-by-step explanation:
as
tanx = sinx/cosx
cotx = cosx/sinx
cscx = 1/sinx
after putting them all in the given equation
sinx.(sinx/cosx).(cosx/sinx).(1/sinx)
they all are canceled as all are being multiplied with their reciprocals so answer is " 1 "
Answer:
Your answer is
$5 after 3.75 miles
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Answer:
0.002 , 0.05 , 0.40 , 0.80 , 1.02 , 2 , 4 , 11 , 13 , 15 , 16 , 357
Step-by-step explanation:
11 , 357 , 2 , 1.02 , 13 , .80 , 4, .002 , 15 , .05 , 16 , .40