Answer:
0.75
Step-by-step explanation:
Answer:
For bbff we have only 6.3% probability
Step-by-step explanation:
If the parents are heterozygous for both traits, them they are represented by:
BbFf × BbFf
Parent 1: BbFf
Parent 2: BbFf
We have to find the percentage of occurence of bb × ff, which is a child that has blue eyes and no freckles, with no dominant factor.
By distributing the possibilities in a Punnett square, <em>vide</em> picture. We have the following possibilities:
Genotype Count Percent
bBfF 4 25
BBfF 2 12.5
bBFF 2 12.5
bBff 2 12.5
bbfF 2 12.5
BBFF 1 6.3
BBff 1 6.3
bbFF 1 6.3
bbff 1 6.3
For bbff we have only 6.3% probability
Answer:
20x
Step-by-step explanation:
You would multiply 1/4 times 8. Or instead, you could divide 80 by 4. You would get 20 then you would multiply that by x and get 20x. Hope this helps.
The answer is a) 35
The steps:
180° - 95 ° = 85 °
180 ° - (85 ° + 60 °)=35 °