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Ivahew [28]
4 years ago
5

What is the ratio 1.12 turned in to a fraction in simplest form?

Mathematics
1 answer:
Nitella [24]4 years ago
5 0
x=1.121212...\ \ \ \ \ |multiply\ both\ sides\ by\ 100\\\\100x=112.121212...\\\\100x-x=112.121212...-1.121212...\\\\99x=111\ \ \ \ |divide\ both\ sides\ by\ 99\\\\x=\dfrac{111:3}{99:3}\\\\x=\dfrac{37}{33}\\\\x=1\dfrac{4}{33}\\\\Answer:\boxed{1.121212...=1\frac{4}{33}}
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If p(x)=2x^3+cx^2+16x+84 and x+2 is a factor of p(x),find the value of c.
Nuetrik [128]

Answer:

c = -9

Step-by-step explanation:

Knowing that -2 is a root, you can do the synthetic division with an unknown value for c. Then solve for the value of c that makes the remainder be zero. See the attachment for the work.

The second attachment shows that (x+2) is a factor of the resulting cubic.

4 0
3 years ago
A circle has a diameter with endpoints at (6, 5) and (8, 5). Write the equation for the circle.
mario62 [17]

Answer:

(x-7)^2+(y-5)^2=1

Step-by-step explanation:

The two things that are required to formulate the equation of the circle is the center coordinate and the radius of the circle!

<u>Center of the circle:</u>

  • The center of the circle always lies at the midpoint of the endpoints of its diameter: Let's call the endpoints A(6,5) and B(8,5).

Using the midpoint formula we'll get:

(x_m, y_m) = \left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

(x_m, y_m) = \left(\dfrac{6+8}{2},\dfrac{5+5}{2}\right)

(x_m, y_m) = (7,5)

This is the center coordinate of our circle.

<u>Radius: </u>

The radius of the circle is the distance from the center of the circle to any of the endpoints of the diameter (A or B)

We can use the distance formula:

r = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

r = \sqrt{(x_1-x_m)^2+(y_1-y_m)^2}

r = \sqrt{(6-7)^2+(5-5)^2}

r = \sqrt{1^2}

r = 1

<u>Equation of the circle: </u>

The equation is written as:

(x-a)^2+(y-b)^2=r^2

here, (a,b) are the center points of the circle

in our case this is (a,b)=(x_m,y_m)=(7,5)

and r = 1

(x-7)^2+(y-5)^2=1^2

(x-7)^2+(y-5)^2=1

This is the equation of the circle!

3 0
3 years ago
Lease someone help me im so confused on how to find it.
LiRa [457]
The answer is D you simply get one point and move it 4 squares down and 6 squares to the right
5 0
3 years ago
The critical points of a rational inequality are –1, 3, and 4. Which set of points can be tested to solve the inequality? x = 1
never [62]

Answer:

x=-3, x=1, x=3.5, and x=5

Step-by-step explanation:

Given the critical points (turning points) which represent the maximum or the minimum points, the set of points that can be tested to solve the inequality will consist of points to the right and to the left of these points. The set of points that solve the inequality will be simply the points where the graph of the function crosses the x-axis. From these information, the set of points will be as given above

4 0
3 years ago
Read 2 more answers
Please awnser i need help on thissss
seraphim [82]
The answer is gonna be (4,3) .
8 0
3 years ago
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