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Paraphin [41]
3 years ago
12

Three even numbers sum up to 162. the smallest is half the largest and the middle number is 3/4 the largest. what are the three

numbers? enter as a comma separated list.
Mathematics
1 answer:
Scrat [10]3 years ago
3 0
Lets name the largest number as x 
smallest number is half the largest , therefore its x/2 = 0.5x
then middle number is 3/4 the largest , therefore its 3/4x = 0.75x
the sum of the three numbers are 162
the three numbers added are 
x + 0.5x + 0.75x = 162
2.25 x = 162
x = 72
the largest number is 72
then middle number 0.75 x = 0.75 x 72 = 54
smallest number is 0.5x = 0.5 x 72 = 36
answer is  -   36,54,72
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4 0
3 years ago
Solve. -1/3b = 9<br> A.-3<br> B.3<br> C.-27<br> D.27
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Ok so lets plug in a first -1/3(-3) would equal 9 a is the accurate  answer
3 0
2 years ago
Read 2 more answers
a person in a whispering gallery standing at one focus of the ellipse can whisper and be heard by a person standing at the other
Lynna [10]

The Height of the ceiling at the center is  57.6628 feet

In geometry, an ellipse is a two-dimensional shape, that is defined along its axes. An ellipse is formed when a cone is intersected by a plane at an angle with respect to its base.

It has two focal points. The sum of the two distances to the focal point, for all the points in curve, is always constant.

The General form of ellipse is \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1

According to the question,

Length of whispering gallery is 130 feet

The foci are located 30feet from the center (0,0)

So, 2a = 130

=> a = 130/2

=> a = 65

and c = 30

As we know ,

=> c² = a² - b²

=> (30)² = (65)² - b²

=> 900 = 4225 - b²

=> b² = 4225 - 900

=> b² = 3325

=> b = 57.7 feet

Therefore , the height of the ceiling at the center is 57.6628 feet

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7 0
8 months ago
There are 20 machines in a factory. 7 of the machines are defective.
adelina 88 [10]

Answer:

0.1225

Step-by-step explanation:

Given

Number of Machines = 20

Defective Machines = 7

Required

Probability that two selected (with replacement) are defective.

The first step is to define an event that a machine will be defective.

Let M represent the selected machine sis defective.

P(M) = 7/20

Provided that the two selected machines are replaced;

The probability is calculated as thus

P(Both) = P(First Defect) * P(Second Defect)

From tge question, we understand that each selection is replaced before another selection is made.

This means that the probability of first selection and the probability of second selection are independent.

And as such;

P(First Defect) = P (Second Defect) = P(M) = 7/20

So;

P(Both) = P(First Defect) * P(Second Defect)

PBoth) = 7/20 * 7/20

P(Both) = 49/400

P(Both) = 0.1225

Hence, the probability that both choices will be defective machines is 0.1225

4 0
3 years ago
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