Answer:
BC + CD = BD
Step-by-step explanation:
The segment addition postulate tells you that when a segment is divided into two parts, the sum of the lengths of the first part of the divided segment and the second part of the divided segment will be equal to the length of the whole segment.
If point C divides segment BD into BC and CD, then the sum of those two segments will match the whole.
So, f(x) is a composite function. This means that g(x) is inside of h(x); in other words, you would substitute g(x) for x in h(x).
Something happened to g(x) (in the form of h(x)) to turn it into f(x). You should notice that f(x) is simply g(x) raised to the third power.
Therefore, h(x) = x^3
You can check this by working it backwards.
Start with: h(x) = x^3
Substitute: x = g(x) = 4x^2-11
Now you have: h(x) = (g(x))^3 = (4x^2-11)^3
Hope this helps!
The answer is three look it up
<h3><em><u>Answers With Steps:</u></em></h3><h3>Question 1:</h3>
For the first problem, understand that you are solving for the area of a circle. The equation for the area of a circle is pi r². By using the leash length as the radius (r), you can get the answer. (The leash length is 3 meters long.)
<em>Question 1 Steps:</em>
pi 3² ---> pi * 9 ---> ≈28.27
<em>Question 1 Answer:</em>
It would have about 28.27 meters² of playable space.
<h3>Question 2:</h3>
For the second problem, it would be much the same as to the first question. There is the same objective to find the area of the circle. Along with that, it gives us a length to work with. This time it is the sprinkler's reach, which would be the radius, or "r" in the equation.
<em>Question 2 Steps:</em>
pi 5² ---> pi * 25 ---> ≈78.54
<em>Question 2 Answer:</em>
The sprinkler would have about 78.54 feet² of space that it can reach.
