Step-by-step explanation:
Initially, let the side of the cubical box is
inches,
So, the volume of the box,
.
Given that ![g(x)=\sqrt[3]{x} =\sqrt[3]{a^3}](https://tex.z-dn.net/?f=g%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D%20%3D%5Csqrt%5B3%5D%7Ba%5E3%7D)

On doubling the volume of the box, the new volume is
.
So, ![g(x)=\sqrt[3]{2x} =\sqrt[3]{2a^3}](https://tex.z-dn.net/?f=g%28x%29%3D%5Csqrt%5B3%5D%7B2x%7D%20%3D%5Csqrt%5B3%5D%7B2a%5E3%7D)
![\Rightarrow g(x)=\sqrt[3]{2} a \; \cdots (i)](https://tex.z-dn.net/?f=%5CRightarrow%20g%28x%29%3D%5Csqrt%5B3%5D%7B2%7D%20a%20%5C%3B%20%5Ccdots%20%28i%29)
As
, so the graph of
will be above of the
as shown in the graph.
100*x I think I’m sorry that’s a poor answer I have done this in years
Answer:
as we know Sara need 8 tube in 3 experiment
she will use 2 tube in 1 experiment
now she have 6 tube in other experiments
so the question said to find how many tube were used in both experiment equally so 3,3 test tube were needed for each of the other two experiment
Step-by-step explanation:
total tube=8 (3 experiment)
used =2tube (1 experiment)
remaining=8-2=6
now ,
dividing 6 into 2 equal part
so,=6/2=3
so 3 tube were used in 2nd experiment and 3in 3rd experiment
3/4x+5/6=5x-125/3
3/4x+5/6-5/6=5x-125/3-5/6
4/3x=5x-85/2
4/3x-5x=5x-5x-85/2
-17/4x=-85/2
(-4*-17/4x)=(-85/2*-4)
17x=170
x=170/17
x=10
(-2,10)
If it is reflected across the x axis then inly the y axis increases