Answer:
![m = \frac{-2}{3}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B-2%7D%7B3%7D)
Explanation:
Given
Points: (1,-1) and (-5,3)
Required
Determine the slope
The slope of a line is represented by m and is calculated as thus;
![m = \frac{y_1 - y_2}{x_1 - x_2}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7By_1%20-%20y_2%7D%7Bx_1%20-%20x_2%7D)
Where
![(x_1,y_1) = (1,-1)](https://tex.z-dn.net/?f=%28x_1%2Cy_1%29%20%3D%20%281%2C-1%29)
![(x_2,y_2) = (-5,3)](https://tex.z-dn.net/?f=%28x_2%2Cy_2%29%20%3D%20%28-5%2C3%29)
Substitute these values in the given formula
![m = \frac{-1 - 3}{1 - (-5)}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B-1%20-%203%7D%7B1%20-%20%28-5%29%7D)
![m = \frac{-1 - 3}{1 +5}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B-1%20-%203%7D%7B1%20%2B5%7D)
![m = \frac{-4}{6}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B-4%7D%7B6%7D)
Simplify fraction
![m = \frac{-2}{3}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B-2%7D%7B3%7D)
Hence, the slope of the line is ![m = \frac{-2}{3}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B-2%7D%7B3%7D)
So, the force that given when the wagon was being pulled is approximately <u>19.1 N (C)</u>.
<h3>Introduction</h3>
Hi ! For intermesso, this question will adopt a lot about the relationship of impulse to change in momentum. <u>Impulse is the total force applied in a certain time interval</u>. Impulses can cause a change of momentum, because momentum itself <u>is a mass that is affected by the velocity of an object</u>. We know that velocity is a vector quantity easy to change its direction. The relationship between impulse and change in momentum is formulated by :
![\sf{I = \Delta p}](https://tex.z-dn.net/?f=%20%5Csf%7BI%20%3D%20%5CDelta%20p%7D%20)
![\sf{F \cdot \Delta t = (m \cdot v') - (m \cdot v)}](https://tex.z-dn.net/?f=%20%5Csf%7BF%20%5Ccdot%20%5CDelta%20t%20%3D%20%28m%20%5Ccdot%20v%27%29%20-%20%28m%20%5Ccdot%20v%29%7D%20)
![\boxed{\sf{\bold{F \cdot \Delta t = m (v' -v)}}}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Csf%7B%5Cbold%7BF%20%5Ccdot%20%5CDelta%20t%20%3D%20m%20%28v%27%20-v%29%7D%7D%7D%20)
With the following condition :
- I = impulse that given (N.s)
= change of momentum (kg.m/s)- F = force that given (N)
- m = mass of the object (kg)
- v = initial velocity (m/s)
- v' = final velocity (m/s)
= interval of the time (s)
<h3>Problem Solving</h3>
We know that :
- m = mass of the object = 25 kg
- v = initial velocity = 0 m/s
- v' = final velocity = 1.8 m/s
= interval of the time = 2.35 s
What was asked :
- F = force that given = ... N
Step by step :
![\sf{F \cdot \Delta t = m (v' -v)}](https://tex.z-dn.net/?f=%20%5Csf%7BF%20%5Ccdot%20%5CDelta%20t%20%3D%20m%20%28v%27%20-v%29%7D%20)
![\sf{F \cdot 2.35 = 25 (1.8 - 0)}](https://tex.z-dn.net/?f=%20%5Csf%7BF%20%5Ccdot%202.35%20%3D%2025%20%281.8%20-%200%29%7D%20)
![\sf{F = \frac{25 (1.8)}{2.35}}](https://tex.z-dn.net/?f=%20%5Csf%7BF%20%3D%20%5Cfrac%7B25%20%281.8%29%7D%7B2.35%7D%7D%20)
![\boxed{\sf{F = 19.15 \: N \approx 19.1 \: N}}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Csf%7BF%20%3D%2019.15%20%5C%3A%20N%20%5Capprox%2019.1%20%5C%3A%20N%7D%7D%20)
<h3>Conclusion</h3>
So, the force that given when the wagon was being pulled is approximately 19.1 N (C).
The right answer for the question that is being asked and shown above is that: "C. <span>. The properties change going across each row. " the </span>statement that applies to the horizontal rows or periods in the periodic table is that t<span>he properties change going across each row. </span>
Answer:
diameter ≅ 3 inches
Explanation:
![HP=k*s*d^{3}](https://tex.z-dn.net/?f=HP%3Dk%2As%2Ad%5E%7B3%7D)
Use a constant factor, k
Let Hp = horsepower
Let s = speed in rpm
Let d = diameter in inches
to find constant k, using
Hp=46
S=100
d=3 in
![46=k*100*3^{3} \\\\46=k*100*27\\46=2700k\\k=\frac{46}{2700} \\k=0.017\\\\](https://tex.z-dn.net/?f=46%3Dk%2A100%2A3%5E%7B3%7D%20%5C%5C%5C%5C46%3Dk%2A100%2A27%5C%5C46%3D2700k%5C%5Ck%3D%5Cfrac%7B46%7D%7B2700%7D%20%5C%5Ck%3D0.017%5C%5C%5C%5C)
To find diameter when;
Hp=74
S=175
k=0.017
d=d inches
d≅ 3 inches
<span>The earth moves, which is unstoppable and if the earth moves the telescope won't be able to see it clearly because the telescope needs to be able to move at the same pace as earth to keep up to the objects</span>