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BARSIC [14]
3 years ago
9

A boy with a mass of 25 kg is sitting in a red wagon of mass 8.5 kg which is at rest. His friend begins pulling him forward, acc

elerating him with a constant force for 2.35 s to a speed of 1.8 m/s. Calculate the force with which the wagon was being pulled.
4.2 N

25.7 N

19.1 N

6.5 N
Physics
1 answer:
tangare [24]3 years ago
6 0

So, the force that given when the wagon was being pulled is approximately <u>19.1 N (C)</u>.

<h3>Introduction</h3>

Hi ! For intermesso, this question will adopt a lot about the relationship of impulse to change in momentum. <u>Impulse is the total force applied in a certain time interval</u>. Impulses can cause a change of momentum, because momentum itself <u>is a mass that is affected by the velocity of an object</u>. We know that velocity is a vector quantity easy to change its direction. The relationship between impulse and change in momentum is formulated by :

\sf{I = \Delta p}

\sf{F \cdot \Delta t = (m \cdot v') - (m \cdot v)}

\boxed{\sf{\bold{F \cdot \Delta t = m (v' -v)}}}

With the following condition :

  • I = impulse that given (N.s)
  • \sf{\Delta p} = change of momentum (kg.m/s)
  • F = force that given (N)
  • m = mass of the object (kg)
  • v = initial velocity (m/s)
  • v' = final velocity (m/s)
  • \sf{\Delta t} = interval of the time (s)

<h3>Problem Solving</h3>

We know that :

  • m = mass of the object = 25 kg
  • v = initial velocity = 0 m/s
  • v' = final velocity = 1.8 m/s
  • \sf{\Delta t} = interval of the time = 2.35 s

What was asked :

  • F = force that given = ... N

Step by step :

\sf{F \cdot \Delta t = m (v' -v)}

\sf{F \cdot 2.35 = 25 (1.8 - 0)}

\sf{F = \frac{25 (1.8)}{2.35}}

\boxed{\sf{F = 19.15 \: N \approx 19.1 \: N}}

<h3>Conclusion</h3>

So, the force that given when the wagon was being pulled is approximately 19.1 N (C).

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