speed equals distance times time
The maximum force acts between B and C as the graph is steepest showing maximum deceleration
The question is how far not how for
Answer:
101.1 m
Explanation:
From the kinematics equations
s=ut-0.5gt^{2} but since u=o and the negative implies the distance is downwards then
s=0.5gt^{2} where s is the distance, u is initial speed, t is time, g is acceleration due to gravity
s=0.5*9.81*4.54^{2}=101.099898
\approx 101.1 m
Answer:
E = 0.13 J
Explanation:
At resonance condition we have
![\omega = \sqrt{\frac{1}{LC}}](https://tex.z-dn.net/?f=%5Comega%20%3D%20%5Csqrt%7B%5Cfrac%7B1%7D%7BLC%7D%7D)
![\omega = \sqrt{\frac{1}{(13.5 \times 10^{-3}}{50\times 10^{-6})}}](https://tex.z-dn.net/?f=%5Comega%20%3D%20%5Csqrt%7B%5Cfrac%7B1%7D%7B%2813.5%20%5Ctimes%2010%5E%7B-3%7D%7D%7B50%5Ctimes%2010%5E%7B-6%7D%29%7D%7D)
![\omega = 1217.2 rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D%201217.2%20rad%2Fs)
now if the frequency is double that of resonance condition then we have
![x_L = 2\omega L](https://tex.z-dn.net/?f=x_L%20%3D%202%5Comega%20L)
![x_L = 2(1217.2)(13.5\times 10^{-3})](https://tex.z-dn.net/?f=x_L%20%3D%202%281217.2%29%2813.5%5Ctimes%2010%5E%7B-3%7D%29)
![x_L = 32.86 ohm](https://tex.z-dn.net/?f=x_L%20%3D%2032.86%20ohm)
now we have
![x_c = \frac{1}{2(1217)(50\times 10^{-6})}](https://tex.z-dn.net/?f=x_c%20%3D%20%5Cfrac%7B1%7D%7B2%281217%29%2850%5Ctimes%2010%5E%7B-6%7D%29%7D)
![x_c = 8.22 ohm](https://tex.z-dn.net/?f=x_c%20%3D%208.22%20ohm)
now average power is given as
![P = i_{rms}V_{rms}\times \frac{R}{z}](https://tex.z-dn.net/?f=P%20%3D%20i_%7Brms%7DV_%7Brms%7D%5Ctimes%20%5Cfrac%7BR%7D%7Bz%7D)
![P = \frac{55}{\sqrt{(32.86 - 8.22)^2 + 13^2)}}(55)\times \frac{13}{\sqrt{(32.86 - 8.22)^2 + 13^2}}](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7B55%7D%7B%5Csqrt%7B%2832.86%20-%208.22%29%5E2%20%2B%2013%5E2%29%7D%7D%2855%29%5Ctimes%20%5Cfrac%7B13%7D%7B%5Csqrt%7B%2832.86%20-%208.22%29%5E2%20%2B%2013%5E2%7D%7D)
![P_{avg} = 50.67 Watt](https://tex.z-dn.net/?f=P_%7Bavg%7D%20%3D%2050.67%20Watt)
Now time period is given as
![T = \frac{2\pi}{\omega}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B2%5Cpi%7D%7B%5Comega%7D)
so total energy consumed is given as
![E_{avg} = 50.67(\frac{2\pi}{2(1217.2)})](https://tex.z-dn.net/?f=E_%7Bavg%7D%20%3D%2050.67%28%5Cfrac%7B2%5Cpi%7D%7B2%281217.2%29%7D%29)
![E = 0.13 J](https://tex.z-dn.net/?f=E%20%3D%200.13%20J)
Answer:
torch will not light up
Explanation:
because the torch itself need two but you placed one so it will not light up