Answer:
The Internet Protocol version 4 (IPv4) is a protocol for use on packet-switched Link Layer networks (e.g. Ethernet). IPv4 provides an addressing capability of approximately 4.3 billion addresses. The Internet Protocol version 6 (IPv6) is more advanced and has better features compared to IPv4.
Explanation:
Without IP addresses, computers would not be able to communicate and send data to each other. It's essential to the infrastructure of the web. A: IPv6 is the sixth revision to the Internet Protocol and the successor to IPv4
Answer:
// Program is written in C++ Programming Language
// Comments are used for explanatory purpose
// Program starts here
#include<iostream>
using namespace std;
int main ()
{
// Declare Variable
int selection;
// Prompt user to make a selection of medium between air, water or steel.
cout<<"Make Selection"<<'\n'<<"Press 1 for Air"<<'\n'<<"Press 2 for Water"<<'\n'<<"Press 3 for Steel";
cin>>selection;
// Check for entry
if(selection == 1) {
cout<<"You selected Air"<<'\n';
cout<<"The distance travelled by sound wave in air is 1,125 feet in 1 second";
}
else if(selection == 2) {
cout<<"You selected Water"<<'\n';
cout<<"The distance travelled by sound wave in water is 4859 feet in 1 second";
}
else if(selection == 3) {
cout<<"You selected Steel"<<'\n';
cout<<"The distance travelled by sound wave in steel is 19554 feet in 1 second";
}
else
cout<<"Invalid Selection";
return 0;
}
Answer:
- def check_subset(l1, l2):
- status = False
- count = 0
- if(len(l1) > len(l2)):
- for x in l2:
- for y in l1:
- if x == y:
- count += 1
-
- if(count == len(l2)):
- return True
- else:
- return False
-
- else:
- for x in l1:
- for y in l2:
- if x==y:
- count += 1
-
- if(count == len(l1)):
- return True
- else:
- return False
-
- print(check_subset([1,4,6], [1,2,3,4,5,6]))
- print(check_subset([2,5,7,9,8], [7,8]))
- print(check_subset([1, 5, 7], [1,4,6,78,12]))
Explanation:
The key idea of this solution is to create a count variable to track the number of the elements in a shorter list whose value can be found in another longer list.
Firstly, we need to check which list is shorter (Line 4). If the list 2 is shorter, we need to traverse through the list 2 in an outer loop (Line 5) and then create another inner loop to traverse through the longer list 1 (Line 6). If the current x value from list 2 is matched any value in list 1, increment the count variable by 1. After finishing the outer loop and inner loop, we shall be able to get the total count of elements in list 2 which can also be found in list 1. If the count is equal to the length of list 2, it means all elements in the list 2 are found in the list 1 and therefore it is a subset of list 1 and return true (Line 10-11) otherwise return false.
The similar process is applied to the situation where the list 1 is shorter than list 2 (Line 15-24)
If we test our function using three pairs of input lists (Line 26-28), we shall get the output as follows:
True
True
False
If I had an array of the names of people who just walked in the door. I’d append the name of the person who came in next. To update the array.
The append method needs to be looped through to add multiple inputs
Correct but men are more prone to it.
