The series converges to 1/(1-9x) for -1/9<x<1/9
Given the series is ∑ 
We have to find the values of x for which the series converges.
We know,
∑ 
converges to (a) / (1-r) if r < 1
Otherwise the series will diverge.
Here, ∑ 
is a geometric series with |r| = | 9x |
And it converges for |9x| < 1
Hence, the given series gets converge for -1/9<x<1/9
And geometric series converges to a/(1-r)
Here, a = 1 and r = 9x
Therefore, a/(1-r) = 1/(1-9x)
Hence, the given series converges to 1/1-9x for -1/9<x<1/9
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The thing that's true about the values p and q is that p = q.
The total <em>sum of the angles</em> in a triangle is 180°.
From the first triangle, the value of p will be:
80° + 20° + p = 180°
100° + p = 180°
p = 180° - 100°
p = 80°
From the second triangle, the value of q will be:
55° + 45° + q = 180°
100° + q = 180°
q = 180° - 100°
q = 80°
Therefore, p = q.
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Can you rewrite the equation? It doesn’t make sense
Answer:
y-coordinate is 5 or -1.
Step-by-step explanation:
Point A is at (x, 2) and B is at (x+6, 2). Since AB must lie on the line y=2 and be 6 units long. Point C is on the line x = -3 . So let C be at (-3, y).
Since ΔABC is a right angle, then point C must have the same x-coordinate as point A. Therefore, A(-3, 2) and B(2, 2).
The area of ΔABC is 6. So,
9 = 1/2 (b)(h)
where b is the base and h is the height.
so b = 6 and h = AC
Solving this for C gives
9 = 1/2 (6)(AC)
18/6 = AC
3 = AC
9 = 1/2 (6)(AC)
18/6 = AC
3 = AC
Point C must lie 3 units above point A or 3 units below the point A. If it lies 3 units above, then it has a y-coordinate of 2 + 3 = 5.
If it lies 3 units below, it has a y-coordinate 2 - 3 = -1.
Therefore, y-coordinate is 5 or -1.
Step-by-step explanation:
