This is a geometric sequence because each term is twice the value of the previous term. So this is what would be called the common ratio, which in this case is 2. Any geometric sequence can be expressed as:
a(n)=ar^(n-1), a(n)=nth value, a=initial value, r=common ratio, n=term number
In this case we have r=2 and a=1 so
a(n)=2^(n-1) so on the sixth week he will run:
a(6)=2^5=32
He will run 32 blocks by the end of the sixth week.
Now if you wanted to know the total amount he runs in the six weeks, you need the sum of the terms and the sum of a geometric sequence is:
s(n)=a(1-r^n)/(1-r) where the variables have the same values so
s(n)=(1-2^n)/(1-2)
s(n)=2^n-1 so
s(6)=2^6-1
s(6)=64-1
s(6)=63 blocks
So he would run a total of 63 blocks in the six weeks.
Answer:
$22.50
Step-by-step explanation:
15% of 150=22.5
I think 6 is the answer. Hopefully I answered your question
Answer:
so the final answer is =17
Step-by-step explanation:
9+12/3=13+4/2=2+1*2=2 the answer is 13+2+2=17
Answer:
E. 396/538
Step-by-step explanation:
The probability that the senior selected will not be from High School B given that the senior did not answer colege:
First, what's the probability of not having answered college? This will be out denominator.
P(not choosing college) = 244 + 106 + 188 = 538
Next, what's the probability that a senior in that category is not from HS B? Well, add the probabilities that the senior is in HS A or C:
P(senior is in HS A or C and answered not college) = 49 + 99 + 63 + 83 + 31 + 71 = 396
<u>Our answer is E. 396/538.</u>
