Range R={-3-11,1,17}
domain D={-9,-3,5}
1.57, divide two times pi (3.14)
The diameter of the sphere is 60 mm which means its radius is 30mm. <span>The radius of a sphere is increasing at a rate of 5 mm/s.
The formula for the radius when the time is x second would be:
</span>r(t)<span>= 30+ 5x
dr/dt= 5
The speed of </span><span>volume increase </span><span>of the sphere volume would be derived from sphere volume:
</span>V(r)=4/3* pi * r^3<span>
dV/dt= 4/3 * pi * 3r^2 * (dr/dt) =4/3* pi * 3(30)^2 * 5 = 18000 pi= 56571 mm^3/s</span>
Answer:
See below.
Step-by-step explanation:
Well first, we need to find the weight of the table. We know that 8 boxes weighs a total of 240kg (since each box weights 30kg). Thus, we can conclude that the table weighs 70kg by doing 310-240=70.
Now, we can write our function. Let
equal the amount of boxes.
The table is a set weight, so that would be our constant.
Thus, we will have:

30x represents the weight each box of book adds to the total. One box equals 30kg, 2 boxes equal 60kg, etc.
The 70 represents the unchanging weight of the table.
In terms of W(x), it will be:

The equation is:
h ( t ) = - 16 t² + 60 t + 3
The toy rocket will reach the ground when: h ( t ) = 0
- 16 t² + 60 t + 3 = 0

t 1 = - 0.05
t 2 = 3.8
Answer:
C ) 3.80 s