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kirill [66]
2 years ago
7

Select the terms which describe various members of the archaea.

Biology
1 answer:
Gala2k [10]2 years ago
7 0
<span>Members of the archaea are complex single-cells organisms that are often thought to be bacteria; however, they are actually prokaryotic microbes that lack a cell nucleus and membrane. They often thrive in extreme conditions such as extreme heat.</span>
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At this stage, the body is dry and mostly bones, cartilage, and dry Skin With oy
Ira Lisetskai [31]

Answer:

i m not sure but the answer may be dry /skeletol

8 0
2 years ago
The synapse is typically located between the _____ of the first (sending) neuron and the _____ of the second (receiving) neuron.
uysha [10]

Answer:

axon; dendrite

Explanation:

A neuron has three main parts. These are axons, dendrites, and a cell body. Synapse is the site of communication between two neurons. The first neuron of a synapse is called the presynaptic neuron (sending neuron) while the second one is called the postsynaptic neuron (receiving). The axon of the presynaptic neuron and the dendrites of the postsynaptic neuron communicate with each other at the synapse as the axon of the first neuron delivers the nerve impulse away from the cell body.

Dendrites function as the receiving or input portions of a neuron. The plasma membranes of dendrites have numerous receptor sites for binding chemical messengers from the presynaptic neuron.

7 0
2 years ago
Calculate the final concentration of BSA in the problems below using the formula
Rudiy27

Answer:

A. C_2=1.5\frac{mg}{mL}

B. C_2=0.075\frac{mg}{mL}

C. C_2=0.01\frac{mg}{mL}

D. C_2=0.001\frac{mg}{mL}

Explanation:

Hello.

In this case, we must compute the final concentration in all the cases so we solve for it in the given equation:

C_2=\frac{C_1V_1}{V_2}

Thus, we proceed as follows:

A. Here, the final diluted solution includes the 300 μL of the 5 mg/ml-BSA and the 700 μL of TBS.

C_2=\frac{300\mu L*5\frac{mg}{mL} }{(300+700)\mu L}\\\\C_2=1.5\frac{mg}{mL}

B. Here, the final diluted solution includes the 50 μL of the 1.5 mg/ml-BSA, the 450 μL of water and the 500 μL of TBS.

C_2=\frac{50\mu L*1.5\frac{mg}{mL} }{(50+450+500)\mu L}\\\\C_2=0.075\frac{mg}{mL}

C. Here, the final diluted solution includes the 10 μL of the 1 mg/ml-BSA and the 990 μL of TBS.

C_2=\frac{10\mu L*1\frac{mg}{mL} }{(10+990)\mu L}\\\\C_2=0.01\frac{mg}{mL}

D. Here, the final diluted solution includes the 10 μL of the 0.1 mg/ml-BSA and the 990 μL of TBS.

C_2=\frac{10\mu L*0.1\frac{mg}{mL} }{(10+990)\mu L}\\\\C_2=0.001\frac{mg}{mL}

Best regards.

7 0
2 years ago
How does photosynthesis yield sugar? sumarize how the light-capturing reactions a?
julsineya [31]
Answer
            Photosynthesis yield sugar in two main steps

1. Light reaction
                           
In this step plant absorb sunlight which cause photolysis of water and excitation of electron. this electron flow through Z-scheme and atlast enter into NADH,  the end product of light reaction is ATP and NADH₂.

2. DArk reaction.
In this step ATP and NADH₂ are used as raw materials. it occurs in stroma of chloroplast. here CO₂ is used through Calvin cycle and at the end glucose is prepared.

6 0
2 years ago
one important difference between living things (biotic) and nonliving things (abiotic) is that only living things have
Mamont248 [21]
The answer is: D. Cells
7 0
2 years ago
Read 2 more answers
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