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frosja888 [35]
3 years ago
12

What is the slope and y-intercept of this line? y = -6 + 2 I'll give brainiest.

Mathematics
1 answer:
QveST [7]3 years ago
3 0
Hello There!!!

if i am doing this correctly 

 2 is your y intercept, this is where the line hits the y line and -6 is your slope 

so you would go down 6 because of the negative and then over to the right one

the reason being you go over one is because under the -6 their is a 1 but it isn't put their, and doesn't have to be.

Hope This Helps!!
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<h3>Answer:  18</h3>

==========================================================

Explanation:

2 cm on paper (or on screen) represents 3 meters in real life.

The backyard is 2 cm horizontally across on the screen, so it's 3 meters across in real life. This is the shorter dimension.

The longer dimension is 6 meters. We can think of it like this

2 cm : 3 meters

2*2 cm : 2*3 meters .... multiply both sides by 2

4 cm : 6 meters

The real backyard is 6 meters by 3 meters to give an area of 6*3 = 18 square meters.

7 0
3 years ago
The two linear functions f(x) and g(x) are shown below.<br> Which of the following is true
Vlada [557]

Answer:

C}

Step-by-step explanation:

5 0
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bagirrra123 [75]

Answer:

thats A daddy-o

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there are 4 out of 12

1/3

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6 0
3 years ago
What is the standard form of the equation of a line for which the length of the normal segment to the origin is 8 and the normal
jeka57 [31]
Slope of line = tan(120) = -tan(60) = - &radic;3
Distance from origin = 8

Let equation be Ax+By+C=0
then -A/B=-&radic;3, or
B=A/&radic;3.
Equation becomes
Ax+(A/&radic;3)y+C=0

Knowing that line is 8 units from origin, apply distance formula
8=abs((Ax+(A/&radic;3)y+C)/sqrt(A^2+(A/&radic;3)^2))
Substitute coordinates of origin (x,y)=(0,0)  =>
8=abs(C/sqrt(A^2+A^2/3))
Let A=1 (or any other arbitrary finite value)
solve for positive solution of C
8=C/&radic;(4/3) => C=8*2/&radic;3 = (16/3)&radic;3

Therefore one solution is
x+(1/&radic;3)+(16/3)&radic;3=0
or equivalently
&radic;3 x + y + 16 = 0

Check:
slope = -1/&radic;3  .....ok
distance from origin
= (&radic;3 * 0 + 0 + 16)/(sqrt(&radic;3)^2+1^2)
=16/2
=8  ok.

Similarly C=-16 will satisfy the given conditions.

Answer  The required equations are
&radic;3 x + y = &pm; 16 
in standard form.

You can conveniently convert to point-slope form if you wish.




4 0
3 years ago
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