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3 years ago

You are baking a casserole. The recipe calls for 1/3 of a cup of beans to

Mathematics

1 answer:

geniusboy [140]3 years ago

8 0

Answer:

2/3

Step-by-step explanation:

Because 7 doubled is 14, you just need to double 1/3 to get your answer. And 1/3 X 2 = 2/3

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What is the value of b^2 0 4ac for the following equation? 2x^2 0 2x 0 1 = 0 04 0 12

tigry1 [53]

2x^2 - 2x - 1 = 0 a = 2, b = -2, c = -1 b^2 - 4ac = (-2)^2 - 4(2)(-1) = 4 + 8 = 12
so the answer is 12

3 0

3 years ago

Two rectangles are similar. If the height of the first rectangle is 3 inches, and the height of the second rectangle is 9 inches

Mrac [35]

The answer is B.) 3

I hope this helped!

8 0

3 years ago

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Please Answer its timed The dimensions of a rectangle are represented by the functions shown. g(x)+3x-4 f(x)=2x-9 Which function

Alenkasestr [34]

Answer:

$\boxed{6x^2-35x+36}$

Step-by-step explanation:

The dimensions of the rectangle are represented by functions:

$g(x)=3x-4 \\f(x)=2x-9$

The area is length × width of a rectangle.

$length \times width$

$(3x-4)(2x-9)$

Expand brackets and solve.

$6x^2-27x-8x+36$

$6x^2-35x+36$

5 0

3 years ago

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NEED THE ANSWER ASAP

quester [9]

Not 100% sure this is right but
60cm^2

8 0

3 years ago

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A vertical cylinder is leaking water at a rate of 4m3/sec. If the cylinder has a height of 10m and a radius of 2m, at what rate

Lyrx [107]

Answer:

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

Step-by-step explanation:

Given that a vertical cylinder is leaking water at rate of 4 m³/s.

It means the rate change of volume is 4 m³/s.

$\frac{dV}{dt}=4 \ m^3/s$

The radius of the cylinder remains constant with respect to time, but the height of the water label changes with respect to time.

The height of the cylinder be h(say).

The volume of a cylinder is $V=\pi r^2 h$

$=( \pi \times 2^2\times h)\ m^3$

$\therefore V= 4\pi h$

Differentiating with respect to t.

$\frac{dV}{dt}=4\pi \frac{dh}{dt}$

Putting the value $\frac{dV}{dt}$

$\Rightarrow 4\pi \frac{dh}{dt}=4$

$\Rightarrow \frac{dh}{dt}=\frac{4}{4\pi}$

$\Rightarrow \frac{dh}{dt}=\frac{1}{\pi}$

The rate change of height does not depend on the height.

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

3 0

3 years ago