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frosja888 [35]
3 years ago
15

How can percents describe a change in area?

Mathematics
1 answer:
Marianna [84]3 years ago
7 0
Divide the change by the initial number to get a fraction and multiply by 100% to get a percent. The percent you get will describe the change in area in the mathematical language of numbers.
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9x+1/2y51<br> 7x+1/3y=39
olga2289 [7]
What’s the question though lol
7 0
3 years ago
If d(x) = x2 - 7x - 7, find d(x - 1).​
satela [25.4K]

Answer: x^2-9x+1

Step-by-step explanation:

x^2-7x-7 d(x-1)

(you would just replace x to (x-1)

(x-1)^2-7(x-1)-7

(solve by square rooting (x-1)(x-1) then foil)

x^2-9x+1

7 0
3 years ago
3v+4(v-2)= -29 solve for v​
Lesechka [4]

Answer:

v = -3

Step-by-step explanation:

1) Expand.

3v + 4v - 8 = -29

2) Simplify 3v + 4v - 8 to 7v - 8.

7v - 8 = -29

3) Add 8 to both sides.

7v = -29 + 8

4) Simplify -29 + 8 to -21.

7v = -21

5) Divide both sides by 7.

v = -21/7

6) Simplify 21/7 to 3.

v = -3

4 0
2 years ago
PLEASE HELP ME D: given the parent function of f(x) = x3, what change will occur when the function is changed to f(x − 3)
Alexxandr [17]
Hello,

Your answer would be:

The parent function is : f ( x ) = x³
f ( x + 3 ) = ( x + 3 )³
shift to the left 3 units.

Plz mark me brainliest!

Hope this helps!
4 0
4 years ago
A machine has four components, A, B, C, and D, set up in such a manner that all four parts must work for the machine to work pro
olchik [2.2K]

Answer:

0.756

Step-by-step explanation:

It is given that a machine has four components, A, B, C, and D.

P(A)=P(B)=0.93, P(C)=0.95,P(D)=0.92

If these components set up in such a manner that all four parts must work for the machine to work properly.

We need to find the probability that the machine works properly. It means we have to find the value of P(A\cap B\cap C\cap D).

If two events X and Y are independent, then

P(X\cap Y)=P(X)\times P(Y)

Assume the probability of one part working does not depend on the functionality of any of the other parts.

P(A\cap B\cap C\cap D)=P(A)\times P(B)\times P(C)\times P(D)

Substitute the given values.

P(A\cap B\cap C\cap D)=0.93\times 0.93\times 0.95\times 0.92

P(A\cap B\cap C\cap D)=0.7559226

P(A\cap B\cap C\cap D)\approx 0.756

Therefore, the probability that the machine works properly is 0.756.

7 0
3 years ago
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