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QveST [7]
3 years ago
9

What are the solutions to 2(x-7)^2 = 32?

Mathematics
1 answer:
MariettaO [177]3 years ago
3 0
2(x-7)^2 = 32\\
(x-7)^2=16\\
x-7=-4 \vee x-7=4\\
x=3 \vee x=11

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3 years ago
Wiat number should be added to both sides of the equation to complete the square? X^2+x=11
Ivahew [28]

Answer:

add 1/4 to each side

Step-by-step explanation:

x^2+x=11

We take the coefficient of the x term

1

Then divide it by 2

1/2

Then square it

(1/2) ^2 = 1/4

Add this to both sides of the equation

x^2 + x + 1/4 = 11+1/4

(x+1/2)^2 = 11 1/4

7 0
4 years ago
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Nancy bought 3.5 gallons of gasoline. she paid 10.43. What was the price per gallon for the gasoline
schepotkina [342]

Answer:

Nancy paid 2.98 per gallon of gasoline.

Step-by-step explanation:

The price of the gasoline is given by the total amount she paid for the gasoline divided by the amount of gasoline acquired with that money. The calculations for this are shown below:

ratio = total money / total gasoline

ratio = 10.43 / 3.5

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Nancy paid 2.98 per gallon of gasoline.

3 0
3 years ago
FIND THE SUM OF 20 TERMS OF THE ARITHMETIC SERIES IN WHICH 3rd TERM IS 7 AND 7th TERM IS 2 MORE THAN THREE TIMES ITS 3rd TERM
algol13

Answer:

740

Step-by-step explanation:

The n th term of an arithmetic series is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₃ = 7 and a₇ = (3 × 7) + 2 = 21 + 2 = 23 , then

a₁ + 2d = 7 → (1)

a₁ + 6d = 23 → (2)

Subtract (1) from (2) term by term

4d = 16 ( divide both sides by 4 )

d = 4

Substitute d = 4 into (1)

a₁ + 2(4) = 7

a₁ + 8 = 7 ( subtract 8 from both sides )

a₁ = - 1

The sum to n terms of an arithmetic series is

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ] , thus

S_{20} = \frac{20}{2} [ (2 × - 1) + (19 × 4) ]

     = 10(- 2 + 76) = 10 × 74 = 740

8 0
3 years ago
Please me ASAP will choose brainliest
pogonyaev
The Least Common Denomiator Is 12
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8 0
4 years ago
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