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guajiro [1.7K]
3 years ago
14

Pedro and Natalia play the trumpet. Pedro

Mathematics
2 answers:
Elza [17]3 years ago
6 0

Answer:

pedro

Step-by-step explanation:

kotegsom [21]3 years ago
3 0

Answer:

Pedro

Step-by-step explanation:

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Y=2x+1 when x increases by 5,y increases by​
Dmitriy789 [7]

Answer:

10

Step-by-step explanation:

say x=0

then y would be 1

increasing x by 5 makes x=5

and then 5 x 2 + 1=11

so y went from 1-11(difference of 10) with the variation

so the answer is 10

3 0
2 years ago
Given: x + y = 15. Which of the following are ordered pairs of this equation?
Dmitry_Shevchenko [17]
(0,5)(1,4)(2,3) I got those
6 0
3 years ago
Read 2 more answers
HELP PLS
olchik [2.2K]

3996  \times  \frac{1}{3}  = 1332
the volume is 1332 in^3


good luck
4 0
3 years ago
Find+the+positive+value+for+α+if+the+radius+of+the+circle+3x^2+3y-6αx+12y-3α=0+is+4
Alik [6]

Answer:

\alpha=3

Step-by-step explanation:

<u>Equation of a Circle</u>

A circle of radius r and centered on the point (h,k) can be expressed by the equation

(x-h)^2+(y-k)^2=r^2

We are given the equation of a circle as

3x^2+3y^2-6\alpha x+12y-3\alpha=0

Note we have corrected it by adding the square to the y. Simplify by 3

x^2+y^2-2\alpha x+4y-\alpha=0

Complete squares and rearrange:

x^2-2\alpha x+y^2+4y=\alpha

x^2-2\alpha x+\alpha^2+y^2+4y+4=\alpha+\alpha^2+4

(x-\alpha)^2+(y+2)^2=r^2

We can see that, if r=4, then

\alpha+\alpha^2+4=16

Or, equivalently

\alpha^2+\alpha-12=0

There are two solutions for \alpha:

\alpha=-4,\ \alpha=3

Keeping the positive solution, as required:

\boxed{\alpha=3}

8 0
3 years ago
A cutting tool fails due to flank wear while machining. It is observed that the tool life at a cutting speed of 160 m/min is 5 m
Ahat [919]

Answer:

The answer is:

30 minutes.

Step-by-step explanation:

We are given the following information:

at 160 m/min, tool life = 5 min.

at 120 m/min, tool life = 17 min.

This means that as the speed reduced from 160 m/min to 120 m/min, the tool life increased from 5 min. to 17 min, hence the difference between the changes are:

speed = 160 - 120 = 40 m/min

tool life = 17 - 5 = 12 min.

Therefore, it can be concluded that a change of speed of 40 m/min, increases the tool life by 12 min.

40 m/min = 12 min

∴ 1 m/min = 12/40 min.

∴ 100 m/min = 12/40 × 100 = 0.3 × 100 =30 min.

8 0
3 years ago
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