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3 years ago

Y and x have a proportional relationship, and y = 12 when x = 5. What is the value of y when x = 8?

1 answer:

8 0

When x = 8 y = 15

The way to figure this out is to subtract 12 by 5. That’s 7 so there’s a difference of 7 between both of the numbers.

Hope this helped!

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Write the expression in repeated multiplication form then write the expression as a power

lord [1]

Repeated multiplication

$(5 \times 5 \times 5 \times 5 \times 5 \times 5)(5 \times 5 \times 5)$

Power

${5}^{9}$

If multiplying something with like bases, add the exponents together.

7 0

3 years ago

Read 2 more answers

Two students from a group of eight boys and 12 girls are sent to represent the school in a parade.If the students are chosen at

jolli1 [7]

Answer:

The probability that the students chosen are not both girls is 62/95 ⇒ (c)

Step-by-step explanation:

* Lets explain how to find the probability of an event

- The probability of an Event = Number of favorable outcomes ÷ Total

number of possible outcomes

- P(A) = n(E) ÷ n(S) , where

# P(A) means finding the probability of an event A

# n(E) means the number of favorable outcomes of an event

# n(S) means set of all possible outcomes of an event

- Probability of event not happened = 1 - P(A)

- P(A and B) = P(A) . P(B)

* Lets solve the problem

- There is a group of students

- There are 8 boys and 12 girls in the group

∴ There are 8 + 12 = 20 students in the group

- The students are sent to represent the school in a parade

- Two students are chosen at random

∴ P(S) = 20

- The students that chosen are not both girls

∴ The probability of not girls = 1 - P(girls)

∵ The were 20 students in the group

∵ The number of girls in the group was 12

∴ The probability of chosen a first girl = 12/20

∵ One girl was chosen, then the number of girls for the second

choice is less by 1 and the total also less by 1

∴ The were 19 students in the group

∵ The number of girls in the group was 11

∴ The probability of chosen a second girl = 11/19

- The probability of both girls is P(1st girle) . P(2nd girl)

∴ The probability of both girls = (12/20) × (11/19) = 33/95

- To find the probability of both not girls is 1 - P(both girls)

∴ P(not both girls) = 1 - (33/95) = 62/95

* The probability that the students chosen are not both girls is 62/95

5 0

3 years ago

Please help me with this!

notsponge [240]

4 babies and 7 adults

B head=4x1=4 Aheads (3x7)=21 21+4=25 heads

B wings 4x2=8 A wings(4x7)=28 28+8=36

4 0

3 years ago

Read 2 more answers

If the prisms below are similar what is the ratio of the surface area of the smaller prism to the surface area of the larger pri

Ronch [10]

The ratio between the surfaces areas of the two prisms is equal to 6.25.

<h3>How to get the ratio of the surface areas?</h3>

The ratio between the volumes of the prisms is:

$R_v = \frac{375 in^3}{24 in^3} = 15.625$

This number is equal to the cube of the scale of dilation applied to the dimensions of the smaller prism, so the scale factor is:

$\sqrt[3]{15.625} = 2.5$

And the ratio between the areas should be the square of the scale factor, then we will have that the ratio between the surface areas of the two prisms is:

$2.5^2 = 6.25$

If you want to learn more about scale factors, you can read:

brainly.com/question/3457976

3 0

2 years ago

A newspaper reports the following changes in the temperature of a city over 4 days:

suter [353]

Answer:Consider the parent equation of a every quadratic equation which is y=^2. which of the following points below meets the requirement by falling in the solution set? y≤x^2 a; y=10,000 b; y=-1.000 c; y=0,5 d; y=17/3

Step-by-step explanation:

8 0

3 years ago