1) The lengths of the other 2 sides are 51 feet.
Isosceles triangles have at least 2 equal sides. The base is 60 feet, so we can assume that the other 2 sides are equal
162 = 60 + 2x
x = the equal sides of the triangle.
162 - 60 = 102
102 = 2x
Divided by 2
51 = x
51 + 51 = 102. 102 + 60 = 162
2)
Pool 1: 311.38ft.
8*19.4 = 155.2
8 * 5.7 * 2 = 91.2
5.7 * 5.7 = 32.49/2 (because its a triangle) = 16.254*4 = 64.98
155.2 + 91.2 + 64.98 = 311.39
Pool 2: Either 863.94ft or 484 + 121πft
22 * 22 = 484
22/2 = 11, So, the radius of the half circle is 11
Circle area = (pi)r^2
11*11 = 121
pi * 121 = 121pi
Using 3.14 substitute: 3.14 * 121 = 379.94
379.94 + 484 = 863.94
Pool 3: 207ft
Rhombus area = pq/2
18 * 12 = 216
216/2 = 108
11 * 18 = 198/2 = 99
99 + 108 = 207
5X^4 + 2X^2 – 8
Its quadratic form is 5(x²)² +2x² -8
<span>Let be X²=p, so the final expression is 5p²+2p-8</span>
Answer:
-⅗ = x
Step-by-step explanation:
Here is what you get when you distribute the -2 on the left side of the equivalence symbol and combine like-terms on the right side of the equivalence symbol:
-2x - 4 = 3x - 1
Here is the solution:
-2x - 4 = 3x - 1
-3x -3x
----------------
-5x - 4 = -1
4 +4
----------------
-5x = 3
----- -----
-5 -5
x = -⅗
I am joyous to assist you anytime.
Answer:
x =2
2 in, 6 in, 1 in
Step-by-step explanation:
